Codeforces Round #253 (Div. 2), problem: (B)【字串匹配】

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簡易字串匹配，題意不難

 1 #include <stdio.h> 2 #include <string.h> 3 #include <math.h> 4 #include <iostream> 5 #include <algorithm> 6 using namespace std; 7  8 int main(){ 9     int i, j, k, t, n;10     int num, flag, ans;11     char a[300];12     scanf("%s",a);13     scanf("%d",&k);14     int len = strlen(a);15     num = len + k;16     num /= 2;17     flag = 0;18     for(n = num; n > 0; --n){19         for(j = 0; j < len; ++j){20             i = j;21             while(i < j + n && i <(len + k - n)){22                 if((i + n) >= len){23                     ++i;24                     continue;25                 }26                 if(a[i] == a[i + n]){27                     ++i;28                     continue;29                 }30                 else    break;31             }32 33             if(i == j + n){34                 flag = 1;35                 break;36             }37         }38         if(flag)    break;39     }40     printf("%d\n",n * 2);41     return 0;42 }