標籤:
題目大意:有n個已知半徑的雪球。堆一個雪人需要三個尺寸不同的雪球,問用這些雪球最多能堆多少個雪人?
題目分析:先統計一下每種尺寸的球的個數,從三種最多的種類中各取出一個堆成雪人,這樣貪心能保證的到的數目最多。
代碼如下:
# include<iostream># include<map># include<vector># include<cstdio># include<queue># include<algorithm>using namespace std;struct Node{ int val,cnt; Node(int _val,int _cnt):val(_val),cnt(_cnt){} bool operator < (const Node &a) const{ return cnt<a.cnt; }};int ans[40005][3],n;map<int,int>mp;priority_queue<Node>q;void solve(){ int cnt=0; while(!q.empty()){ Node a=q.top(); q.pop(); if(q.empty()) break; Node b=q.top(); q.pop(); if(q.empty()) break; Node c=q.top(); q.pop(); ans[cnt][0]=a.val; ans[cnt][1]=b.val; ans[cnt][2]=c.val; ++cnt; if(a.cnt-1>0) q.push(Node(a.val,a.cnt-1)); if(b.cnt-1>0) q.push(Node(b.val,b.cnt-1)); if(c.cnt-1>0) q.push(Node(c.val,c.cnt-1)); } printf("%d\n",cnt); for(int i=0;i<cnt;++i){ sort(ans[i],ans[i]+3); printf("%d %d %d\n",ans[i][2],ans[i][1],ans[i][0]); }}int main(){ int a; while(~scanf("%d",&n)) { mp.clear(); for(int i=0;i<n;++i){ scanf("%d",&a); ++mp[a]; } map<int,int>::iterator it; while(!q.empty()) q.pop(); for(it=mp.begin();it!=mp.end();++it){ q.push(Node(it->first,it->second)); } solve(); } return 0;}
CoderForce 140C-New Year Snowmen(貪心)