常用演算法(C#): 求一個數的最小公倍數

來源:互聯網
上載者:User

using System;
using System.Collections.Generic;
using System.Text;

namespace ExMinGongBeiShu
{
    class MinGongBeiShu
    {
        public float minGongBeiShu(int n1, int n2)
        {
            int temp = Math.Max(n1, n2);
            n2 = Math.Min(n1, n2);//n2中存放兩個數中最小的
            n1 = temp;//n1中存放兩個數中最大的
            int product = n1 * n2;//求兩個數的乘積
            while (n2 != 0)
            {
                n1 = n1 > n2 ? n1 : n2;//使n1中的數大於n2中的數
                int m = n1 % n2;
                n1 = n2;
                n2 = m;
            }

            return (product/n1);//最小公倍數
        }
        static void Main(string[] args)
        {
            int n1 = Convert.ToInt32(Console.ReadLine());
            int n2 = Convert.ToInt32(Console.ReadLine());
            if (n1 * n2 != 0)
            {
                MinGongBeiShu m = new MinGongBeiShu();
                Console.WriteLine("{0}和{1}的最小公倍數為{2}",n1,n2,m.minGongBeiShu(n1, n2));
            }
            else
            {
                Console.WriteLine("這兩個數不能為0。");
            }
        }
    }
}

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