MongoDB文法與現有關係型資料庫SQL文法比較

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進入，查看，使用

 

 進入  mongodb show dbsuse mydatabase show collections db["mycol"].find({},{_id:0,name:1})  # 第一個參數為條件，第二個參數為顯示結果設定 

db["mycol"].inseret({"key":"value",title:"tutorial",name:"jkmiao"})

MongoDB文法與現有關係型資料庫SQL文法比較MongoDB文法                                  MySql文法db.test.find({‘name‘:‘foobar‘})<==> select * from test where name=‘foobar‘db.test.find()                            <==> select *from testdb.test.find({‘ID‘:10}).count()<==> select count(*) from test where ID=10db.test.find().skip(10).limit(20)<==> select * from test limit 10,20db.test.find({‘ID‘:{$in:[25,35,45]}})<==> select * from test where ID in (25,35,45)db.test.find().sort({‘ID‘:-1})  <==> select * from test order by IDdescdb.test.distinct(‘name‘,{‘ID‘:{$lt:20}})  <==> select distinct(name) from testwhere ID<20 db.test.group({key:{‘name‘:true},cond:{‘name‘:‘foo‘},reduce:function(obj,prev){prev.msum+=obj.marks;},initial:{msum:0}})  <==> select name,sum(marks) from testgroup by name db.test.find(‘this.ID<20‘,{name:1})  <==> select name from test whereID<20 db.test.insert({‘name‘:‘foobar‘,‘age‘:25})<==>insertinto test (‘name‘,‘age‘) values(‘foobar‘,25) db.test.remove({})                        <==> delete * from testdb.test.remove({‘age‘:20})            <==> delete test where age=20db.test.remove({‘age‘:{$lt:20}})   <==> elete test where age<20db.test.remove({‘age‘:{$lte:20}})  <==> delete test where age<=20db.test.remove({‘age‘:{$gt:20}})  <==> delete test where age>20db.test.remove({‘age‘:{$gte:20}})<==> delete test where age>=20db.test.remove({‘age‘:{$ne:20}})  <==> delete test where age!=20 db.test.update({‘name‘:‘foobar‘},{$set:{‘age‘:36}})<==> update test set age=36 where name=‘foobar‘db.test.update({‘name‘:‘foobar‘},{$inc:{‘age‘:3}})<==> update test set age=age+3 where name=‘foobar‘

 

MongoDB文法與現有關係型資料庫SQL文法比較