電腦學院大學生程式設計競賽（2015’12）The Magic Tower

The Magic Tower Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 2382    Accepted Submission(s): 615


Problem Description Like most of the RPG (role play game), “The Magic Tower” is a game about how a warrior saves the princess. 
After killing lots of monsters, the warrior has climbed up the top of the magic tower. There is a boss in front of him. The warrior must kill the boss to save the princess.
Now, the warrior wants you to tell him if he can save the princess.  
Input There are several test cases.
For each case, the first line is a character, “W” or “B”, indicating that who begins to attack first, ”W” for warrior and ”B” for boss. They attack each other in turn. 
The second line contains three integers, W_HP, W_ATK and W_DEF. (1<=W_HP<=10000, 0<=W_ATK, W_DEF<=65535), indicating warrior’s life point, attack value and defense value. 
The third line contains three integers, B_HP, B_ATK and B_DEF. (1<=B_HP<=10000, 0<=B_ATK, B_DEF<=65535), indicating boss’s life point, attack value and defense value. 

Note: warrior can make a damage of (W_ATK-B_DEF) to boss if (W_ATK-B_DEF) bigger than zero, otherwise no damage. Also, boss can make a damage of (B_ATK-W_DEF) to warrior if (B_ATK-W_DEF) bigger than zero, otherwise no damage. 
 
Output For each case, if boss’s HP first turns to be smaller or equal than zero, please print ”Warrior wins”. Otherwise, please print “Warrior loses”. If warrior cannot kill the boss forever, please also print ”Warrior loses”.
 
Sample Input

W 100 1000 900 100 1000 900 B 100 1000 900 100 1000 900  
Sample Output

Warrior wins Warrior loses  

總是望著曾經的空間發獃，那些說好不分開的朋友不在了，轉身，陌路。 熟悉的，安靜了， 安靜的，離開了， 離開的，陌生了， 陌生的，消失了， 消失的，陌路了。

#include <stdio.h>#include <stdlib.h>int main(){    char a;    int i,W_HP,W_ATK,W_DEF,B_HP,B_ATK,B_DEF,w_b,b_w;    while(~scanf("%c",&a))    {        scanf("%d%d%d%d%d%d%*c",&W_HP,&W_ATK,&W_DEF,&B_HP,&B_ATK,&B_DEF);        w_b=W_ATK-B_DEF;        //w對b每一次攻擊的數值        if(w_b<0) w_b=0;        b_w=B_ATK-W_DEF;        //b對w每一次攻擊的數值        if(b_w<0) b_w=0;        if(a=='W')        {            for(i=1;i>=1;i++)            {                if(w_b==0)                {                    printf("Warrior loses\n");                    break;                }                B_HP-=w_b;                if(B_HP<0)                {                    printf("Warrior wins\n");                    break;                }                W_HP-=b_w;                if(W_HP<0)                {                    printf("Warrior loses\n");                    break;                }            }        }        if(a=='B')        {            for(i=1;i>=1;i++)            {                if(w_b==0)                {                    printf("Warrior loses\n");                    break;                }                W_HP-=b_w;                if(W_HP<0)                {                    printf("Warrior loses\n");                    break;                }                B_HP-=w_b;                if(B_HP<0)                {                    printf("Warrior wins\n");                    break;                }            }        }    }    return 0;}

@執念  "@☆但求“”安★ 下次我們做的一定會更好。。。。
為什麼這次的題目是英文的。。。。QAQ...