標籤:es2017 [] next mail https 算術運算 ascii lock http
看到有人問的程式,就去寫了幾行代碼,順便複習一下條件陳述式和ASCII碼
1 import java.util.Scanner; 2 public class test1 { 3 4 public static void main(String[] args) 5 { 6 Scanner sc = new Scanner(System.in); 7 System.out.print("輸入一個ASCII數值:"); 8 int ascii = sc.nextInt(); 9 sc.close();10 char ch = (char)ascii;11 //在‘a’~‘z’轉成‘A’~‘Z’12 if(ch >= ‘a‘ && ch <= ‘z‘)13 {14 System.out.println((char)(ch-32));15 }16 //在‘A’~‘Z’轉成‘a’~‘z’17 else if(ch >= ‘A‘ && ch <= ‘Z‘)18 {19 System.out.println((char)(ch+32));20 }21 //在‘0’~‘9’輸出0~922 else if(ch >= ‘0‘ && ch <= ‘9‘)23 {24 System.out.println(ch);25 }26 //輸出“+ - * /”27 else if(ch == ‘+‘ || ch== ‘-‘ || ch == ‘*‘ || ch == ‘/‘)28 {29 System.out.println("屬於算術運算子");30 }31 //輸出“非法字元”32 else33 {34 System.out.println("非法字元");35 }36 }37 }
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