刪除複選框選中的資料，不管選中多少，傳過去的值只有一個，請哪裡的有關問題

問題：

刪除複選框選中的資料，不管選中多少，傳過去的值只有一個，請哪裡的問題

<br><table width="49%" cellspacing="1" bgcolor="#0093C4" id='demotable1'><br>   <thead><br>     <tr><br>       <th width="3%"><INPUT name="chkAll" id="chkAll" title="全選" onClick="ChkAllClick('delivery[]','chkAll')" type="checkbox" /></th><br>       <th width="8%" class="STYLE3">Item Code</th><br>       <th width="12%" class="STYLE3">SKU</th><br>       <th width="15%" class="STYLE3">ASIN</th><br>       <th width="21%" class="STYLE3">Description</th><br>       <th width="12%" class="STYLE3">Type</th><br>       <th width="9%" class="STYLE3">Delivery Areas</th><br>       <th width="10%" class="STYLE3">Account</th><br>       <th width="10%" class="STYLE3">FNSKU</th><br>     </tr><br>   </thead><br>   <tbody><br>     <?PHP<br>  while($row = mysql_fetch_array($result, MYSQL_ASSOC)) {<br>  ?><br>     <tr><br>       <td><input type="checkbox" name="delivery[]" value="<?PHP echo $row['id']; ?>" /></td><br>       <td><?PHP echo $row['item_code'] ?></td><br>       <td><?PHP echo $row['sku'] ?></td><br>       <td><?PHP echo $row['asin'] ?></td><br><br><br>

<br>function delClick(){  <br>var val = $('input:checked').val();    <br> window.location.href="http://www.php1.cn/"><br>} <br>

<br><br>        <input type="button" class="btn" id="add_btn"  value="新 增" /><br>       <br>          <input name="button" type="button" class="btn" onclick="delClick()" value="刪 除" /><br>

<br>    case 'del' : //刪除<br>    <br>$id=$_GET["delivery"];<br>$SQL = "delete from `sku_rule` where id in($id)";<br>        $result = mysql_query($SQL);<br>        if (mysql_affected_rows($conn) != 1){<br>        <br>            echo "<script>alert('刪除失敗!');location.href="http://www.php1.cn/">        } else {<br>        <br>            echo "<script>alert('刪除成功!');location.href="http://www.php1.cn/">        }<br>        break;<br>

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