django 字元編碼出錯解決方案

學習limodou的step by step，根據第七章的例子，要完成一個address book。 os ：debian etch locale: zh_CN.UTF-8 django 1.0 python2.4.4 address/models.py 內容如下 #coding=utf-8 2 3 from django.db import models 4 5 # Create your models here. 6 7 class Address(models.Model): 8 name = models.CharField('姓名',max_length=20,unique=True) 9 gender = models.CharField('性別',choices=(('M','男'),('F','女')), 10 max_length=1 ) 11 telephone = models.CharField('電話',max_length=20) 12 mobile = models.CharField('手機',max_length=11) 13 14 15 class Admin: 16 pass 在admin的介面下可以完成address對象的添加和儲存，點擊Address object，可以 把記錄內容正確顯示出來。接著根據例子，在給class Address加入 def __str__(self): return self.name 在admin的介面中可以看到address object的名字顯示出來，但是點擊名字要顯示 內容時出現如下錯誤：   TemplateSyntaxError at /admin/address/address/1/ Caught an exception while rendering: 'ascii' codec can't encode characters in position 0-2: ordinal not in range(128) Original Traceback (most recent call last):   File "/usr/lib/python2.4/site-packages/django/template/debug.py", line 71, in render_node     result = node.render(context)   File "/usr/lib/python2.4/site-packages/django/template/debug.py", line 87, in render     output = force_unicode(self.filter_expression.resolve(context))   File "/usr/lib/python2.4/site-packages/django/template/__init__.py", line 559, in resolve     new_obj = func(obj, *arg_vals)   File "/usr/lib/python2.4/site-packages/django/template/defaultfilters.py", line 31, in _dec     args[0] = force_unicode(args[0])   File "/usr/lib/python2.4/site-packages/django/utils/encoding.py", line 52, in force_unicode     s = unicode(str(s), encoding, errors) UnicodeEncodeError: 'ascii' codec can't encode characters in position 0-2: ordinal not in range(128) 解決方案：__str__() 改成 __unicode__() Django升級到1.0之後有一些變化，還有那個class Admin也不再用於產生管理介面了