實驗要求
設有二元函數 f(x,y) = f(x) + f(y)
其中: f(x) = f(x-1) * x (x >1)
f(x)=1 (x=1)
f(y) = f(y-1) + f(y-2) (y> 2)
f(y)=1 (y=1,2)
請編程建立 3 個並發協作進程,它們分別完成 f(x,y)、f(x)、f(y)
實驗代碼
/* *exp2.c */#include<stdio.h>#include<stdlib.h>#include<unistd.h>int calcfy(int y){ if(y==1||y==2){ return 1; }else{ return calcfy(y-1)+calcfy(y-2); }}int main(int argc,char *argv[]){ int pid1; int pid2; int pipe1[2]; int pipe2[2]; printf("Please input x y:"); int x,y; scanf("%d %d",&x,&y); printf("x=%d, y=%d\n",x,y); if(x<1||y<1){ perror("bad input\n"); exit(EXIT_FAILURE); } if(pipe(pipe1)<0){ perror("pipe not create"); exit(EXIT_FAILURE); } if(pipe(pipe2)<0){ perror("pipe not create"); exit(EXIT_FAILURE); } pid1=fork(); if(pid1<0){ perror("process not create\n"); exit(EXIT_FAILURE); }else if(pid1==0){ int fx; close(pipe1[0]); for(fx=1;x>1;x--){ fx*=x; } write(pipe1[1],&fx,sizeof(int)); close(pipe1[1]); }else{ pid2=fork(); if(pid2<0){ perror("process not create\n"); exit(EXIT_FAILURE); }else if(pid2==0){ int fy; close(pipe2[0]); fy=calcfy(y); write(pipe2[1],&fy,sizeof(int)); close(pipe2[1]); }else{ int fx,fy; read(pipe1[0],&fx,sizeof(int)); read(pipe2[0],&fy,sizeof(int)); printf("I'm %d\n",getpid()); printf("Get fx=%d from %d\n",fx,pid1); printf("Get fy=%d from %d\n",fy,pid2); printf("f(x,y)=%d\n",fx+fy); return EXIT_SUCCESS; } }}
#makefilecc=gccsrc=exp2.cobj=exp2.oexp2:$(obj)$(cc) $(obj) -o $@exp2.o:$(cc) -c $(src)clean:rm *.o
實驗結果