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基於代數方程庫Algebra.js解二元一次方程功能樣本，代數方程algebra.js
本文執行個體講述了基於代數方程庫Algebra.js解二元一次方程功能。分享給大家供大家參考，具體如下：
假設二元一次方程如下：
x + y = 11x - y = 5
解方程如下：
<!DOCTYPE html><html lang="zh-CN"><head> <meta charset="UTF-8" /> <meta http-equiv="X-UA-Compatible" content="IE=edge,chrome=1" /> <title>測試algebra函數庫（解兩元一次方程）</title> <script src="js/algebra.min.js"></script> <script type="text/javascript"> var Fraction = algebra.Fraction; var Expression = algebra.Expression; var Equation = algebra.Equation; //======================================= var x1 = algebra.parse("x+y=11"); var answer1 = x1.solveFor("y"); //console.log("y = " + answer1.toString()); var x2 = algebra.parse("x-y=5"); var answer2 = x2.solveFor("y"); //console.log("y = " + answer2.toString()); //================================================= //解出X值 var eq = new Equation(answer1, answer2); console.log("x運算式：" + eq.toString()); var answerX = eq.solveFor("x"); console.log("解出X的值為：" + answerX.toString()); //================================================= //解出Y值（把x的值代入x1或x2） eq = x1.eval({ x: answerX }); console.log("y運算式：" + eq.toString()); var answerY = eq.solveFor("y"); console.log("解出Y的值為：" + answerY.toString()); </script></head><body></body></html>
控制台輸出：
x運算式：-x + 11 = x - 5解出X的值為：8y運算式：y + 8 = 11解出Y的值為：3
代碼寫得很粗曠，無任何封裝。看得懂就好。
algebra.min.js可訪問其官方網站下載：http://algebra.js.org/
或者點擊此處本站下載。
PS：這裡再為大家推薦幾款計算工具供大家進一步參考借鑒：
線上一元函數（方程）求解計算工具：
http://tools.jb51.net/jisuanqi/equ_jisuanqi
科學計算機線上使用_進階計算機線上計算：
http://tools.jb51.net/jisuanqi/jsqkexue
線上計算機_標準計算機：
http://tools.jb51.net/jisuanqi/jsq
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