擷取羅輯思維每天的微信語音(python)，羅輯python

擷取羅輯思維每天的語音(python)，羅輯python
擷取羅輯思維每天的語音(python)by 伍雪穎
一直喜歡聽羅輯思維,不過每天去點那個的公眾號好麻煩,而且每天聽一分鐘也不太爽,於是今天突然想把它們全pa下來,合并起來,找時間一次全聽完不更好.於是,開動:上網找了下,發現已經有一個網站有mp3,於是去爬它的資料(也可以直接去爬羅輯思維官網的資料http://www.ljsw.cc)http://www.ljsw.cc/forum-39-1.html擷取title和mp3的url:#coding=utf-8
import re,urllib2

f = file('luoji.txt','w')

def getHtmlCode(url):
    return urllib2.urlopen(url).read()

def getTitle(htmlString):
    regTitle = re.compile("xst\">(.+?) ")
        returnregTitle.findall(htmlString)

def getMp3Url(htmlString):
    regMp3 = re.compile("http(.+?).mp3\'")
        returnregMp3.findall(htmlString)

def getLuojiContent(url):
    htmlCode = getHtmlCode(url)
        titles = getTitle(htmlCode)
        urls = getUrl(htmlCode)
        for i in range(0,len(urls)):
            printtitles[i]
                f.write(titles[i] + '-')
                contentHtml = getHtmlCode(urls[i])
                contents = getMp3Url(contentHtml)
                iflen(contents) > 0:
                    mp3Url = 'http' + contents[0] +'.mp3'
                        print mp3Url
                        f.write(mp3Url + '\n')


if __name__ == '__main__':
    for i in range(1,38):
        printstr(i)
            url = 'http://www.ljsw.cc/forum-39-'+ str(i) + '.html'
            try:
                getLuojiContent(url)
                print'finished: ' + str(i)
            except:
                printstr(i) + ': error!'

下載mp3檔案:#coding=utf-8
import re,urllib2,os

for line in open("luoji.txt"):
    contents = line.split('-')
        url = line[11:len(line)-1]
        cmd = 'curl -O "%s"'% (url)
        os.system(cmd)
        fileName = url.split('/')
        name = fileName[len(fileName) - 1]
        os.rename(name,contents[0] +'.mp3')

合并mp3檔案:from glob import iglob
import shutil
import os

PATH = r'mp3'
destination = open('luoji.mp3','wb')
for filename in iglob(os.path.join(PATH, '*.mp3')):
    shutil.copyfileobj(open(filename, 'rb'), destination)destination.close()
搞定,於是可以一個個聽,也可以合起來聽

所有python代碼:github代碼

所有mp3檔案:連結: http://pan.baidu.com/s/1nt5L7Pf 密碼: 5mrg