Gym 100342E Minima

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讀懂題意就可以做了,單調隊列維護區間最小值就行了。

#include<bits/stdc++.h>using namespace std;typedef long long ll;const int maxn = 3e7+5;int x[maxn], dq[maxn], pos[maxn];int main(){    freopen("minima.in","r",stdin);    freopen("minima.out","w",stdout);    int n,m,k; cin>>n>>m>>k;    ll a,b,c; cin>>a>>b>>c;    for(int i = 1; i <= k; i++) scanf("%d",x+i);    for(int i = k+1; i <= n; i++){        ll t = a*x[i-2]+b*x[i-1]+c;        x[i] = t;    }    int l = 0,r = 0;    ll ans = 0;    for(int i = 1; i <= n; i++){        while(r>l && dq[r-1]>=x[i]) r--;        dq[r] = x[i];        pos[r++] = i;        if(i-pos[l] >= m) l++;        if(i>=m) ans+= dq[l];    }    printf("%I64d\n",ans);    return 0;}

 

Gym 100342E Minima

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