標籤:hat can contains memory 暴力 break 特殊 uri number
傳送門:
http://acm.hdu.edu.cn/showproblem.php?pid=1017
A Mathematical Curiosity
Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 47658 Accepted Submission(s): 15285
Problem DescriptionGiven two integers n and m, count the number of pairs of integers (a,b) such that 0 < a < b < n and (a^2+b^2 +m)/(ab) is an integer.
This problem contains multiple test cases!
The first line of a multiple input is an integer N, then a blank line followed by N input blocks. Each input block is in the format indicated in the problem description. There is a blank line between input blocks.
The output format consists of N output blocks. There is a blank line between output blocks.
InputYou will be given a number of cases in the input. Each case is specified by a line containing the integers n and m. The end of input is indicated by a case in which n = m = 0. You may assume that 0 < n <= 100.
OutputFor each case, print the case number as well as the number of pairs (a,b) satisfying the given property. Print the output for each case on one line in the format as shown below.
Sample Input110 120 330 40 0
Sample OutputCase 1: 2Case 2: 4Case 3: 5
Source分析:直接暴力即可code:
#include<bits/stdc++.h>using namespace std;typedef long long LL;#define max_v 105int main(){ int t; int n,m; scanf("%d",&t); while(t--) { int k=1; while(~scanf("%d %d",&n,&m)) { if(n==0&&m==0) break; int c=0; //直接暴力即可 for(int i=1; i<n-1; i++) { for(int j=i+1; j<n; j++) { if((i*i+j*j+m)%(i*j)==0) c++; } } printf("Case %d: %d\n",k++,c); } if(t!=0) printf("\n"); } return 0;}
HDU 1017A Mathematical Curiosity (暴力統計特殊要求個數)