標籤:java acm
問題:
開始嘗試用字元做數組元素,但是並沒有用。在判斷語句時把a z排出了。
An easy problem
Time Limit: 1000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 16516 Accepted Submission(s): 11096
Problem Descriptionwe define f(A) = 1, f(a) = -1, f(B) = 2, f(b) = -2, ... f(Z) = 26, f(z) = -26;
Give you a letter x and a number y , you should output the result of y+f(x).
InputOn the first line, contains a number T.then T lines follow, each line is a case.each case contains a letter and a number.
Outputfor each case, you should the result of y+f(x) on a line.
Sample Input
6R 1P 2G 3r 1p 2g 3
Sample Output
191810-17-14
代碼:
import java.util.*;public class Main{public static void M1(char str,int kk){char aa[]={'A','B','C','D','E','F','G','H','I','J','K','L','M','N','O','P','Q','R','S','T','U','V','W','X','Y','Z'};for(int i=0;i<26;i++){if(aa[i]==str)System.out.println((i+1)+kk);}}public static void M2(char str,int kk){char aa[]={'a','b','c','d','e','f','g','h','i','j','k','l','m','n','o','p','q','r','s','t','u','v','w','x','y','z'};for(int i=0;i<26;i++){if(aa[i]==str)System.out.println(-(i+1)+kk);}}public static void main(String[] args) {Scanner cin=new Scanner(System.in);int nn=cin.nextInt();for(int ii=0;ii<nn;ii++){String st=cin.next();int kk=cin.nextInt();char a[]=st.toCharArray();char str=a[0];if(str>='a'&&str<='z')M2(str,kk);else if(str>='A'&&str<='Z')M1(str,kk);}}}
hdu 2055 An easy problem (java)