標籤:
Harry and Magical Computer
Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 499 Accepted Submission(s): 233
Problem DescriptionIn reward of being yearly outstanding magic student, Harry gets a magical computer. When the computer begins to deal with a process, it will work until the ending of the processes. One day the computer got n processes to deal with. We number the processes from 1 to n. However there are some dependencies between some processes. When there exists a dependencies (a, b), it means process b must be finished before process a. By knowing all the m dependencies, Harry wants to know if the computer can finish all the n processes.
InputThere are several test cases, you should process to the end of file.
For each test case, there are two numbers n m on the first line, indicates the number processes and the number of dependencies. 1≤n≤100,1≤m≤10000
The next following m lines, each line contains two numbers a b, indicates a dependencies (a, b). 1≤a,b≤n
OutputOutput one line for each test case.
If the computer can finish all the process print "YES" (Without quotes).
Else print "NO" (Without quotes).
Sample Input3 23 12 13 33 22 11 3
Sample OutputYESNO
#include <cstdio>#include <cmath>#include <cstring>#include <ctime>#include <iostream>#include <algorithm>#include <set>#include <vector>#include <sstream>#include <queue>#include <typeinfo>#include <fstream>typedef long long ll;using namespace std;//freopen("D.in","r",stdin);//freopen("D.out","w",stdout);#define sspeed ios_base::sync_with_stdio(0);cin.tie(0)#define maxn 100001const int inf=0x7fffffff; //無限大 int map[101][101];int vis[101];int flag[101];int main(){ int n,m; while(cin>>n>>m) { memset(map,0,sizeof(map)); memset(vis,0,sizeof(vis)); memset(flag,0,sizeof(flag)); int a,b; for(int i=0;i<m;i++) { cin>>a>>b; map[b-1][a-1]=1; flag[a-1]=1; } queue<int> q; for(int i=0;i<n;i++) { if(flag[i]==0) { q.push(i); vis[i]=1; } } int now; int next; while(!q.empty()) { now=q.front(); for(int i=0;i<n;i++) { if(map[now][i]==1) { if(vis[i]==1) continue; q.push(i); vis[i]=1; } } q.pop(); } int flag1=0; for(int i=0;i<n;i++) { if(vis[i]==0) { flag1=1; break; } } if(flag1==1) cout<<"NO"<<endl; else cout<<"YES"<<endl; }}
HDU 5154 Harry and Magical Computer bfs