Android發送xml資料給伺服器的方法_Android

本文執行個體講述了Android發送xml資料給伺服器的方法。分享給大家供大家參考。具體如下：

一、發送xml資料：

public static void main(String[] args) throws Exception { String xml = "<?xml version=\"1.0\" encoding=\"UTF-8\"?><videos><video><title>中國</title></video></videos>"; String path = http://localhost:8083/videoweb/video/manage.do?method=getXML ; byte[] entity = xml.getBytes("UTF-8"); HttpURLConnection conn = (HttpURLConnection) new URL(path).openConnection(); conn.setConnectTimeout(5000); conn.setRequestMethod("POST"); conn.setDoOutput(true); //指定發送的內容類型為xml conn.setRequestProperty("Content-Type", "text/xml; charset=UTF-8"); conn.setRequestProperty("Content-Length", String.valueOf(entity.length)); OutputStream outStream = conn.getOutputStream(); outStream.write(entity); if(conn.getResponseCode() == 200){  System.out.println("發送成功"); }else{  System.out.println("發送失敗"); }}

二、接受xml資料：

public ActionForward getXML(ActionMapping mapping, ActionForm form,  HttpServletRequest request, HttpServletResponse response)  throws Exception { InputStream inStream = request.getInputStream(); byte[] data = StreamTool.read(inStream); String xml = new String(data, "UTF-8"); System.out.println(xml); return mapping.findForward("result");}

希望本文所述對大家的Android程式設計有所協助。