php實現統計網站線上人數的方法

 　　本文執行個體講述了php實現統計網站線上人數的方法。分享給大家供大家參考。具體實現方法如下：

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<?php function getIpAddress() { // 取得目前使用者的IP地址 if (getenv('HTTP_CLIENT_IP')) { $ip = getenv('HTTP_CLIENT_IP'); } elseif (getenv('HTTP_X_FORWARDED_FOR')) { $ip = getenv('HTTP_X_FORWARDED_FOR'); } elseif (getenv('REMOTE_ADDR')) { $ip = getenv('REMOTE_ADDR'); } else { $ip = $_SERVER['REMOE_ADDR']; } return $ip; } function writeover($filename,$data,$method = 'w',$chmod = 0){ $handle = fopen($filename, $method); !handle && die("檔案開啟失敗"); flock($handle, LOCK_EX); fwrite($handle, $data); flock($handle, LOCK_UN); fclose($handle); $chmod && @chmod($filename, 0777); } function count_online_num($time, $ip) { $fileCount = './count.txt'; $count = 0; $gap = 900; //15分鐘不重新整理頁面就 if (!file_exists($fileCount)) { $str = $time . "t" . $ip . "rn"; writeover($fileCount, $str, 'w', 1); $count = 1; } else { $arr = file($fileCount); $flag = 0; foreach($arr as $key => $val) { $val= trim($val); if ($val != "") { list($when, $seti) = explode("t", $val); if ($seti ==$ip) { $arr[$key] = $time . "t" . $seti; $flag = 1; } else { $currentTime = time(); if ($currentTime - $when > 900) { unset($arr[$key]); }else{ $arr[$key]=$val; } } } } if ($flag == 0) { array_push($arr, $time . "t" . $ip); } $count = count($arr); $str = implode("rn", $arr); $str.="rn"; writeover($fileCount, $str, 'w', 0); unset($arr); } return $count; } $time = time(); $ip = getIpAddress(); $online_num = count_online_num($time,$ip); echo $online_num; ?>

　　希望本文所述對大家的php程式設計有所協助。