怎麼把數組的值變成健名形成新的數組

如何把數組的值變成健名形成新的數組。
本帖最後由 xuexi123abc163 於 2014-11-24 11:40:57 編輯

(
[0] => Array
(
[ak] => 1
[fs] => 12
[tss] => sd第三方f
)

[1] => Array
(
[ak] => 2
[fs] => 12
[tss] => 是的發生
)

[2] => Array
(
[ak] => 3
[fs] => 22
[tss] => 好新玩
)

[3] => Array
(
[ak] => 4
[fs] => 22
[tss] => 八實得分
)
[4] => Array
(
[ak] => 6
[fs] => 22
[tss] => 八實得分
)
)

上面的數組是$abc
我下奶想形成新的數組把fs的值作為鍵名，然後把fs的值相同的，形成新的數組，。。

數組如下：

(
[12] => Array
(
[0] => Array
(
[ak] => 2
[tss] => 是的發生
)
[1] => Array
(
[ak] => 2
[tss] => 是的發生
)
)

[22] => Array
(
...............
)
)





------解決思路----------------------

$ar = array (
  array (
    'ak' => '1',
    'fs' => '12',
    'tss' => 'sd第三方f',
  ),
  array (
    'ak' => '2',
    'fs' => '12',
    'tss' => '是的發生',
  ),
  array (
    'ak' => '3',
    'fs' => '22',
    'tss' => '好新玩',
  ),
  array (
    'ak' => '4',
    'fs' => '22',
    'tss' => '八實得分',
  ),
  array (
    'ak' => '6',
    'fs' => '22',
    'tss' => '八實得分',
  ),
);
$res = array();
foreach($ar as $r) {
  $t = $r['fs'];
  unset($r['fs']);
  $res[$t][] = $r;
}
print_r($res);

Array
(
    [12] => Array
        (
            [0] => Array
                (
                    [ak] => 1
                    [tss] => sd第三方f
                )

            [1] => Array
                (
                    [ak] => 2
                    [tss] => 是的發生
                )

        )

    [22] => Array
        (
            [0] => Array
                (
                    [ak] => 3
                    [tss] => 好新玩
                )

            [1] => Array
                (
                    [ak] => 4
                    [tss] => 八實得分
                )

            [2] => Array
                (
                    [ak] => 6
                    [tss] => 八實得分
                )

        )

)

