怎樣得到迴圈的兩個鄰近的數值的差

怎樣得到迴圈的兩個相鄰的數值的差
function get_shijian_list($school_id,$parent_id)
{
$sql = "select shijian_id,name,type from ".$fdyu->table('oa_shijian')." where parent_id=".$parent_id." and school_id=".$school_id." order by shijian_id asc";
$res = $db->query($sql);
$arr = array();
if($res)
{
while($row = $db->fetchRow($res))
{
//學員總人數
$xy_count = $db->getOne("SELECT COUNT(distinct xy.xy_id) FROM ".
$fdyu->table('oa_xueyuan')." as xy left join ".
$fdyu->table('oa_banji')." as bj on xy.cur_banji_id=bj.banji_id
(bj.shijian_1=".$row['shijian_id']." or bj.shijian_2=".$row['shijian_id']." or bj.shijian_3=".$row['shijian_id'].")
");

$sj_id= $row['shijian_id'];
$arr[$sj_id]['sj_id']= $sj_id;
$arr[$sj_id]['xy_count_s']= $xy_count;
}
}
return $arr;
｝

請問在迴圈中的$xy_count，怎樣計算兩個相鄰的差，比如，得到的$xy_count分別是100、80、50，怎樣得到
100-80=20
80-50-30
------解決思路----------------------
簡單點可以用for

$arr = array(1,2,3,4);
for($i=0,$len=count($arr); $i<$len; $i++){
if($i>0){
echo $arr[$i]-$arr[$i-1];
}
}
------解決思路----------------------

$last = '';
while($row = $db->fetchRow($res))
{
  //學員總人數
  $xy_count = $db->getOne("SELECT COUNT(distinct xy.xy_id) FROM ".
  if($last !== '') echo $last - $xy_count; //這裡是列印，實際需要是什麼你自己定
  $last = $xy_count; 

  //其他代碼
}

