如何在oracle和Mysql中限制返回結果集的大小
在Oracle中如下:
如何正確利用Rownum來限制查詢所返回的行數?
軟體環境:
1、Windows NT4.0+ORACLE 8.0.4
2、ORACLE安裝路徑為:C:/ORANT
含義解釋:
1、rownum是oracle系統順序分配為從查詢返回的行的編號,返回的第一行分配的是1,第二行是2,
依此類推,這個偽欄位可以用於限制查詢返回的總行數。
2、rownum不能以任何基表的名稱作為首碼。
使用方法:
現有一個商品銷售表sale,表結構為:
month char(6) --月份
sell number(10,2) --月銷售金額
create table sale (month char(6),sell number);
insert into sale values('200001',1000);
insert into sale values('200002',1100);
insert into sale values('200003',1200);
insert into sale values('200004',1300);
insert into sale values('200005',1400);
insert into sale values('200006',1500);
insert into sale values('200007',1600);
insert into sale values('200101',1100);
insert into sale values('200202',1200);
insert into sale values('200301',1300);
insert into sale values('200008',1000);
commit;
SQL> select rownum,month,sell from sale where rownum=1;(可以用在限制返回記錄條數的地方,保證不出錯,如:隱式遊標)
ROWNUM MONTH SELL
--------- ------ ---------
1 200001 1000
SQL> select rownum,month,sell from sale where rownum=2;(1以上都查不到記錄)
沒有查到記錄
SQL> select rownum,month,sell from sale where rownum>5;
(由於rownum是一個總是從1開始的偽列,Oracle 認為這種條件不成立,查不到記錄)
沒有查到記錄
只返回前3條紀錄
SQL> select rownum,month,sell from sale where rownum<4;
ROWNUM MONTH SELL
--------- ------ ---------
1 200001 1000
2 200002 1100
3 200003 1200
如何用rownum實現大於、小於邏輯?(返回rownum在4—10之間的資料)(minus操作,速度會受影響)
SQL> select rownum,month,sell from sale where rownum<10
2 minus
3 select rownum,month,sell from sale where rownum<5;
ROWNUM MONTH SELL
--------- ------ ---------
5 200005 1400
6 200006 1500
7 200007 1600
8 200101 1100
9 200202 1200
想按日期排序,並且用rownum標出正確序號(有小到大)
SQL> select rownum,month,sell from sale order by month;
ROWNUM MONTH SELL
--------- ------ ---------
1 200001 1000
2 200002 1100
3 200003 1200
4 200004 1300
5 200005 1400
6 200006 1500
7 200007 1600
11 200008 1000
8 200101 1100
9 200202 1200
10 200301 1300
查詢到11記錄.
可以發現,rownum並沒有實現我們的意圖,系統是按照記錄入庫時的順序給記錄排的號,rowid也是順序分配的
SQL> select rowid,rownum,month,sell from sale order by rowid;
ROWID ROWNUM MONTH SELL
------------------ --------- ------ ---------
000000E4.0000.0002 1 200001 1000
000000E4.0001.0002 2 200002 1100
000000E4.0002.0002 3 200003 1200
000000E4.0003.0002 4 200004 1300
000000E4.0004.0002 5 200005 1400
000000E4.0005.0002 6 200006 1500
000000E4.0006.0002 7 200007 1600
000000E4.0007.0002 8 200101 1100
000000E4.0008.0002 9 200202 1200
000000E4.0009.0002 10 200301 1300
000000E4.000A.0002 11 200008 1000
查詢到11記錄.
正確用法,使用子查詢
SQL> select rownum,month,sell from (select month,sell from sale group by month,sell) where rownum<13;
ROWNUM MONTH SELL
--------- ------ ---------
1 200001 1000
2 200002 1100
3 200003 1200
4 200004 1300
5 200005 1400
6 200006 1500
7 200007 1600
8 200008 1000
9 200101 1100
10 200202 1200
11 200301 1300
按銷售金額排序,並且用rownum標出正確序號(有小到大)
SQL> select rownum,month,sell from (select sell,month from sale group by sell,month) where rownum<13;
ROWNUM MONTH SELL
--------- ------ ---------
1 200001 1000
2 200008 1000
3 200002 1100
4 200101 1100
5 200003 1200
6 200202 1200
7 200004 1300
8 200301 1300
9 200005 1400
10 200006 1500
11 200007 1600
查詢到11記錄.
利用以上方法,如在列印報表時,想在查出的資料中自動加上行號,就可以利用rownum。
返回第5—9條紀錄,按月份排序
SQL> select * from (select rownum row_id ,month,sell
2 from (select month,sell from sale group by month,sell))
3 where row_id between 5 and 9;
ROW_ID MONTH SELL
---------- ------ ----------
5 200005 1400
6 200006 1500
7 200007 1600
8 200008 1000
9 200101 1100
==================================================================================
在Mysql中:
下面是一些學習如何用MySQL解決一些常見問題的例子。
一些例子使用資料庫表“shop”,包含某個商人的每篇文章(物品號)的價格。假定每個商人的每篇文章有一個單獨的固定價格,那麼(物品
,商人)是記錄的主鍵。
你能這樣建立例子資料庫表:
CREATE TABLE shop (
article INT(4) UNSIGNED ZEROFILL DEFAULT '0000' NOT NULL,
dealer CHAR(20) DEFAULT '' NOT NULL,
price DOUBLE(16,2) DEFAULT '0.00' NOT NULL,
PRIMARY KEY(article, dealer));
INSERT INTO shop VALUES
(1,'A',3.45),(1,'B',3.99),(2,'A',10.99),(3,'B',1.45),(3,'C',1.69),
(3,'D',1.25),(4,'D',19.95);
好了,例子資料是這樣的:
SELECT * FROM shop
+---------+--------+-------+
| article | dealer | price |
+---------+--------+-------+
| 0001 | A | 3.45 |
| 0001 | B | 3.99 |
| 0002 | A | 10.99 |
| 0003 | B | 1.45 |
| 0003 | C | 1.69 |
| 0003 | D | 1.25 |
| 0004 | D | 19.95 |
+---------+--------+-------+
3.1 列的最大值
“最大的物品號是什嗎?”
SELECT MAX(article) AS article FROM shop
+---------+
| article |
+---------+
| 4 |
+---------+
3.2 擁有某個列的最大值的行
“找出最貴的文章的編號、商人和價格”
在ANSI-SQL中這很容易用一個子查詢做到:
SELECT article, dealer, price
FROM shop
WHERE price=(SELECT MAX(price) FROM shop)
在MySQL中(還沒有子查詢)就用2步做到:
用一個SELECT語句從表中得到最大值。
使用該值編出實際的查詢:
SELECT article, dealer, price
FROM shop
WHERE price=19.95
另一個解決方案是按價格降序排序所有行並用MySQL特定LIMIT子句只得到的第一行:
SELECT article, dealer, price
FROM shop
ORDER BY price DESC
LIMIT 1
注意:如果有多個最貴的文章( 例如每個19.95),LIMIT解決方案僅僅顯示他們之一!
3.3 列的最大值:按組:只有值
“每篇文章的最高的價格是什嗎?”
SELECT article, MAX(price) AS price
FROM shop
GROUP BY article
+---------+-------+
| article | price |
+---------+-------+
| 0001 | 3.99 |
| 0002 | 10.99 |
| 0003 | 1.69 |
| 0004 | 19.95 |
+---------+-------+
3.4 擁有某個欄位的組間最大值的行
“對每篇文章,找出有最貴的價格的交易者。”
在ANSI SQL中,我可以用這樣一個子查詢做到:
SELECT article, dealer, price
FROM shop s1
WHERE price=(SELECT MAX(s2.price)
FROM shop s2
WHERE s1.article = s2.article)
在MySQL中,最好是分幾步做到:
==========================================================================
14. 如何在mysql中建立表 ?
答:試下這個 ..
CREATE TABLE pictures( picture_id INT UNSIGNED NOT NULL AUTO_INCREMENT,
category_id SMALLINT UNSIGNED NOT NULL,
location VARCHAR(40),
thumb VARCHAR(40),
title VARCHAR(80) NOT NULL,
description TINYTEXT,
last_modified DATE,
last_viwed DATE,
view_count INT UNSIGNED,
user_id VARCHAR(20) NOT NULL,
colour ENUM('true','false') NOT NULL DEFAULT 'true',
PRIMARY KEY (picture_id),
INDEX (title),
INDEX (user_id),
INDEX (category_id),
INDEX (colour) );
15. 如何在M個紀錄中只列出N個,並用翻頁的方法列出其它?
答:可以採用MYSQL的LIMIT函數.
注意:下面的代碼用了cgi-lib.pl的函數來擷取網頁輸入資料.
sub List_Result{
my ($user_action) = @_;
my %cgi_data;
&ReadParse(%cgi_data);
my $limit = 10 ;
my $offset = $cgi_data{'offset'};
my $printed = $cgi_data{'printed'};
my $prev_offset = $cgi_data{'prev_offset'};
my $next_action = $cgi_data{'next_action'};
my $print_cnt = 0;
$new_prev_offset = $offset;
#下面的代碼取得使用者的操作
if ($next_action eq "Next"){
$offset += $limit;
}
elsif($next_action eq "Previous"){
if ($printed < $limit){
$offset = $prev_offset;
}else{
$offset -= $printed;
}
}
else { $offset = 0 ; }
}
my $SELECT ;
my $LIMIT = " LIMIT $offset,$limit";
# 如果$KEEP_SQL 為空白,則表示重新開始,用舊的sql語句
if ($KEEP_SQL eq ""){
if($user_action eq "list_all"){
$SELECT = "SELECT * FROM mytable ";
}
else{
$SELECT = "SELECT * FROM mytable WHERE rec_id = $rec_id ";
}
}else{
$SELECT = $KEEP_SQL;
}
my $SQL = $SELECT.$LIMIT;
# KEEP_SQL將被儲存在一個隱含的表段輸入中,這個變數保證每次都用一個sql語句.
my $KEEP_SQL = $SELECT;
my $sth = $dbh->prepare($SQL);
$sth->execute() or die "Can't execute:";
# 做你想做的事情.
print " [form method=post action=$this_cgi] ...
... 列出結果 ..
[input type=hidden name=offset value=$offset]
[input type=hidden name=printed value=$printed]
[input type=hidden name=prev_offset value=$new_prev_offset]
[input type=hidden name=user_action value=viewing_result]
[input type=hidden name=KEEP_SQL value=$KEEP_SQL] ";
if ($offset > 0 ) {print "[input type=submit name=next_action width=100 value="Previous"]n"; }
if ($printed == $limit){ print "[input type=submit name=next_action width=100 value="Previous"n"]; }
print "[/form]";
16. 如何獲得表的欄位資訊?
答:
#!/usr/bin/perl
# connect to db
my $dbh = DBI->connect(bla..bla..bla);
my $sql_q = "SHOW COLUMNS FROM $table";
my $sth = $dbh->prepare($sql_q);
$sth->execute;
while (@row = $sth->fetchrow_array){
print"Field Type Null Key Default Extran";
print"---------------------------------------------------------------n";
print"$row[0] $row[1] $row[2] $row[3] $row[4] $row[5]n";
}
17. 如何添加一個超級使用者 ?
答: 你可以用GRANT語句:
shell> mysql --user=root mysql
mysql> GRANT ALL PRIVILEGES ON *.* TO monty@localhost IDENTIFIED BY 'something' WITH GRANT OPTION;
mysql> GRANT ALL PRIVILEGES ON *.* TO monty@"%" IDENTIFIED BY 'something' WITH GRANT OPTION;
超級使用者可以從任何地方串連伺服器,但必須使用一個密碼('something').
請注意我們同時對monty@localhost和monty@"%"用了GRANT語句.如果不加上localhost,當我們(超級使用者)從本機上串連時,localhost上
mysql_install_db建立的匿名使用者會取得更高的優先權,因為它有更特別的Host欄位值,使得在使用者列表中佔據靠前的位置.
18.如何知道Mysql伺服器中所有可供使用的資料庫?
答: 用data_sources($driver_name)方法.
這個方法返回SQL伺服器中資料庫名字列表
例: $db_names = DBI->data_sources("mysql");
19. 如何串連SQL伺服器?
答:
#!/usr/bin/perl
use DBI;
my $database_name = "db_name";
my $location = "localhost";
my $port_num = "3306"; # 這是mysql的預設
值 # 定義SQL伺服器的位置.
my $database = "DBI:mysql:$database_name:$location:$port_num";
my $db_user = "user_name";
my $db_password = "user_password";
# 串連.
my $dbh = DBI->connect($database,$db_user,$db_password);
# 做你要做的事情.. ... ...
$dbh->disconnect;
$exit;
20. 如何從SQL伺服器上擷取記錄資料?
答:從SQL伺服器上擷取記錄資料,必須先串連伺服器,然後提交SQL查詢語句,伺服器則返回結果
#!/usr/bin/perl
# 串連伺服器 (見22)
my $sql_statement = "SELECT first_name,last_name FROM $table ORDER BY first_name";
my $sth = $dbh->prepare($sql_statement);
my ($first, $last);
# 結果儲存在$sth中 $sth->execute() or die "無法執行SQL語句:
$dbh->errstr"; $sth->bind_columns(undef, $first, $last);
my $row; while ($row = $sth->fetchrow_arrayref) {
print "$first $lastn";
# 或者
print "$row->[0] $row[1]n";
}
以上的程式將列出結果中的每一行,列印出first name和last name.這是最快的提取資料的方法之一.
21. 如何從伺服器隨機地提取記錄?
答: 用Mysql的LIMIT函數.
$Query = "SELECT * FROM Table";
$sth = $dbh->prepare($Query);
$numrows = $sth->execute;
$randomrow = int(rand($numrows));
$sth = $dbh->prepare("$Query LIMIT $randomrow,1");
$sth->execute;
@arr = $sth->fetchrow;
22. 插入記錄後,如何獲得自動增加的主索引值?
答: insertid方法是MySQL特有的,也許不能在其它SQL server上工作
#!/usr/bin/perl
# 串連資料庫 ....
my $sql_statement = "INSERT INTO $table (field1,field2) VALUES($value1,$value2)";
my $sth = $dbh->prepare($sql_statement);
$sth->execute or die "無法添加資料 :
$dbh->errstr";
# 現在我們可以取回剛剛插入後產生的主鍵.
my $table_key = $sth->{insertid};
# 也可以用這種方法(標準的DBI方法)
my $table_key = $dbh->{'mysql_insertid'};
$sth->finish;
23. 執行SELECT查詢以後,如何獲得記錄行數?
答:有好幾種方法可以做到.這是其中的一種:
# 文檔中說這種方法不行,但對我來說卻可以,你或許也行.
my $mysql_q = "SELECT field1,field2 FROM $table WHERE field1=$value1";
my $sth = $dbh->prepare($mysql_q);
my $found = $sth->execute or die "無法執行 :
$dbh->errstr";
$sth->finish;
# 這是一種較慢的方法,而且做SELECT查詢時還不太可靠.
my $sql = q(select * from $table where field = ? );
my $sth = $dbh->prepare($sql);
$sth->execute('$value');
my $rows = $sth->rows;
$sth->finish;
# 這是一種較快的方法.
my $sql = q(select count(*) from $table where field = ? );
my $sth = $dbh->prepare($sql); $sth->execute('$value');
my $rows = $sth->fetchrow_arrayref->[0];
$sth->finish;
24. 為什麼SELECT LAST_INSERT_ID(USER_ID) FROM User返回的是所有的user id而不是最後一個?
答: 摘自手冊:
"在伺服器上最後建立的ID是根據每個串連來單獨管理的.也就是說,它不能被另外一個用戶端改變. 甚至你用一個非空和非零的值來更新另外一
個AUTO_INCREMENT欄位,它也不會改變. 如果算式做為一個參量賦給UPDATE語句中的LAST_INSERT_ID(),則參量會返回LAST_INSERT_ID()的值."
你真正需要的是: SELECT USER_ID FROM User ORDER BY USER_ID DESC LIMIT 1
25. WHERE語句中可否使用兩個條件?
答: 可以
my $sql_statment = "SELECT * FROM $table WHERE $field1='$value1' AND $field2='$value2'";
26. 如何在多個欄位中尋找一個關鍵字?
答: 試下這個:
SELECT concat(last,' ',first,' ',suffix,' ',year,' ',phone,' ',email) AS COMPLEAT, last, first, suffix, year, dorm, phone,
box, email
FROM Student HAVING COMPLEAT
LIKE '%value1%' AND COMPLEAT LIKE '%value2%' AND COMPLEAT LIKE '%value3%'
27.如何找到一個星期前建立的記錄?
答: 我們需要用DATE函數來做sql查詢:
DATE_ADD(date,INTERVAL expr type)
DATE_SUB(date,INTERVAL expr type)
ADDDATE(date,INTERVAL expr type)
SUBDATE(date,INTERVAL expr type)
例如 : # 這個查詢語句返回所有"年齡"小於或等於7天的記錄
my $sql_q = "SELECT * FROM $database WHERE DATE_ADD(create_date,INTERVAL 7 DAY) >= NOW() ORDER BY create_date DESC";
28.如何取回所有欄位的資料並用"column_name" => value來放入一個相關的數組中?
答:用$sth->fetchrow_hashref 方法.
$SQL = "SELECT * FROM members";
my $sth = $dbh->prepare($SQL);
$sth->execute or die "sql語句錯誤 ".
$dbh->errstr;
my $record_hash;
while ($record_hash = $sth->fetchrow_hashref){
print "$record_hash->{first_name} $record_hash->{last_name}n";
}
$sth->finish;
29.如何儲存一個影像檔(JPG和GIF)到資料庫中?
答:
file: test_insert_jpg.pl
-------------------------
#! /usr/bin/perl
use DBI;
open(IN,"/imgdir/bird.jpg");
$gfx_file=join('',);
close(IN);
$database="speedy";
$table="archive";
$user="stephen";
$password="none";
$dsn="DBI:mysql:$database";
$dbh=DBI->connect($dsn, $user, $password);
$sql_statement=<<"__EOS__";
insert into $table (id, date, category, caption, content, picture1, picture2,
picture3, picture4, picture5, source, _show) values(?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ? )
__EOS__
# uncomment to debug sql statement
# --------------------------------
#open(SQLLOG,">>sql_log_file");
#print SQLLOG scalar(localtime)."t$sql_statementn";
#close(SQLLOG);
$sth=$dbh->prepare($sql_statement);
$sth->execute(NULL,NULL,"car|sports","Porsche Boxster S","German excellence",$gfx_file,NULL,NULL,NULL,NULL,"European
Car","Y");
$sth->finish(); $sth=$dbh->prepare("SELECT * FROM $table");
$sth->execute();
while($ref=$sth->fetchrow_hashref()){
print "id = $ref->{'id'}tcategory = $ref->{'category'}tcaption = $ref->{'caption'}n";
}
$numRows=$sth->rows;
$sth->finish();
$dbh->disconnect();
file: serve_gfx.cgi
-----------------------------------------------------
#!/usr/bin/perl
$|=1;
use DBI;
$database="speedy";
$table="archive";
$user="stephen";
$password="none";
$dsn="DBI:mysql:$database";
$dbh=DBI->connect($dsn, $user,$password);
$sth=$dbh->prepare("select * from $table where id=1");
$sth->execute();
$ref=$sth->fetchrow_hashref();
print "content-type: image/jpgnn";
print $ref->{'picture1'};
$numRows=$sth->rows;
$sth->finish();
$dbh->disconnect();
30. 如何插入N個記錄?
答:
# 讓我們插入10000個記錄
my $rec_num = 10000;
my $PRODUCT_TB = "products";
my $dbh = DBI->connect($database,$db_user,$db_password) or die "無法串連資料庫n";
my $sth = $dbh->prepare("INSERT INTO $PRODUCT_TB (name,price,description,pic_location) VALUES (?,?,?,?)");
for ($i = 1; $i <= $rec_num; $i++){
my $name = "Product $i";
my $price = rand 350;
my $desc = "Desccription of product $i";
my $pic = "images/product/product".$i.".jpg";
$sth->execute($name,$price,$desc,$pic);
}
$sth->finish();
print "完成插入$rec_num個記錄到表$PRODUCT_TBn";
$dbh->disconnect;
exit;
31.如何建立一個date欄位,使其預設值是新記錄建立時的日期?
答:有很多種方法可以做到:
(1) 用TIMESTAMP
Create Table mytable( table_id INT NOT NULL AUTO_INCREMENT,
value VARCHAR(25),
date TIMESTAMP(14),
PRIMARY KEY (table_id) );
當插入或更新記錄時,TIMESTAMP欄位將自動地設定成當前日期.如果你不想更新時改變日期,可在用UPDATE語句時,把日期欄位設定成原來的(插
入日期).
(2) 用NOW()函數.
Create Table mytable( table_id INT NOT NULL AUTO_INCREMENT,
value VARCHAR(25),
date DATE,
PRIMARY KEY (table_id) );
在insert語句中設定date=NOW().