利用jsp和Servlet實現自己的原生JavaEE MVC架構

最後更新：2015-05-11 來源：互聯網

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標籤：mvc servlet jsp

MVC是什麼我就不多說了，我們平時做JavaWeb項目時，大都會用SSH架構的不同組合，那能不能不用SSH架構來實現一個原生的MVC架構呢？

下面就讓我們來實現一個自己的javaWeb MVC架構。

項目結構如下：

Controler的實現：

package com.shu.controler;import java.io.IOException;import javax.servlet.ServletException;import javax.servlet.http.HttpServlet;import javax.servlet.http.HttpServletRequest;import javax.servlet.http.HttpServletResponse;import com.shu.action.Action;import com.shu.action.ActionFactory;/** * ControlerServlet,控制器類，所有的以.action結尾的請求都會被改控制器攔截， *例如：http://localhost:8080/mvc/LoginAction.action * @author Administrator * */public class ControlerServlet extends HttpServlet {/** *  */private static final long serialVersionUID = 4660044561652707132L;@Overrideprotected void doGet(HttpServletRequest req, HttpServletResponse resp)throws ServletException, IOException {doPost(req, resp);}@Overrideprotected void doPost(HttpServletRequest req, HttpServletResponse resp)throws ServletException, IOException {String pathName = req.getServletPath();System.out.println("pathName:" + pathName);int index = pathName.indexOf(".");String actionName = pathName.substring(1,index);System.out.println("actionName:" + actionName);String actionClass = getInitParameter(actionName);System.out.println("actionClass:" + actionClass);Action action = ActionFactory.getAction(actionName);String viewUrl = action.execute(req, resp);if (viewUrl == null) {req.getRequestDispatcher("error.jsp").forward(req, resp);} else {req.getRequestDispatcher(viewUrl).forward(req, resp);}}}

Action介面：

package com.shu.action;import javax.servlet.http.HttpServletRequest;import javax.servlet.http.HttpServletResponse;/** * Action 介面，所有的業務action類都需要實現此介面 * execute方法返回view資源的引用字串，比如“admin/login.jsp” *  * @author Administrator * */public interface Action {public String execute(HttpServletRequest request, HttpServletResponse response);}

Action工廠：

package com.shu.action;import com.shu.actions.LoginAction;/** * 該工廠根據傳入的Action名字返回具體的業務action執行個體 * @author Administrator * */public class ActionFactory {public static Action getAction(String actionName) {if (LoginAction.class.getSimpleName().equals(actionName)) {return new LoginAction();}return null;}}

使用者登入業務Action：

package com.shu.actions;import javax.servlet.http.HttpServletRequest;import javax.servlet.http.HttpServletResponse;import com.shu.action.Action;/** * 處理使用者登入的action類 * @author Administrator * */public class LoginAction implements Action {@Overridepublic String execute(HttpServletRequest request,HttpServletResponse response) {String username = request.getParameter("username");String password = request.getParameter("password");request.setAttribute("username", username);request.setAttribute("password", password);if (username != null && username.trim().length() != 0 && password != null && password.trim().length() != 0) {return "admin/success.jsp";}return "admin/login.jsp";}}

web.xml:

<?xml version="1.0" encoding="UTF-8"?><web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"xmlns="http://java.sun.com/xml/ns/javaee"xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd"id="WebApp_ID" version="2.5"><servlet><servlet-name>controlerServlet</servlet-name><servlet-class>com.shu.controler.ControlerServlet</servlet-class><init-param><param-name>LoginAction</param-name><param-value>com.shu.actions.LoginAction</param-value></init-param></servlet><servlet-mapping><servlet-name>controlerServlet</servlet-name><url-pattern>*.action</url-pattern></servlet-mapping></web-app>

視圖View層：login.jsp

<%@ page language="java" contentType="text/html; charset=ISO-8859-1"    pageEncoding="ISO-8859-1"%><!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd"><html><head><meta http-equiv="Content-Type" content="text/html; charset=ISO-8859-1"><title>Login</title></head><body><form action="<%=request.getContextPath() %>/LoginAction.action" method="post">username:<input type="text" name="username"/><br>password:<input type="password" name="password"/><br><input type="submit" name="Login"/><br></form></body></html>

success.jsp:

<%@ page language="java" contentType="text/html; charset=ISO-8859-1"    pageEncoding="ISO-8859-1"%><!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd"><html><head><meta http-equiv="Content-Type" content="text/html; charset=ISO-8859-1"><title>Insert title here</title></head><body><h1>Success!</h1>username:<%=request.getParameter("username") %><p>password:<%=request.getParameter("password") %><p></body></html>

測試：

利用jsp和Servlet實現自己的原生JavaEE MVC架構

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