java 產生有序帳號的實現方法_java

來源:互聯網
上載者:User

如下所示:

for (int i= 0; i<= 1084; i++) {if (String.valueOf(i+1).length() == 1) {username = "sys_000" + (i+1);}if (String.valueOf(i+1).length() == 2) {username = "sys_00" + (i+1);}if (String.valueOf(i+1).length() == 3) {username = "sys_0" + (i+1);}if (String.valueOf(i+1).length() == 4) {username = "sys_" + (i+1);}System.out.println(username);}
sys_0001sys_0002sys_0003sys_0004sys_0005sys_0006sys_0007sys_0008sys_0009sys_0010sys_0011sys_0012sys_0013sys_0014sys_0015sys_0016sys_0017sys_0018sys_0019sys_0020sys_0021sys_0022sys_0023sys_0024sys_0025sys_0026sys_0027sys_0028sys_0029sys_0030sys_0031sys_0032sys_0033sys_0034sys_0035sys_0036

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