12. Integer to Roman(C++)

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標籤:tor   integer   input   for   public   c++   ++   ring   rom   

Given an integer, convert it to a roman numeral.

Input is guaranteed to be within the range from 1 to 3999.

 

Solution:

以3999,為例:

class Solution {
public:
  string intToRoman(int num) {
    if(num<1||num>3999) return NULL;
    string str;
    while(num){
      if(num/1000!=0){
        for(int i=0;i<num/1000;i++) str+="M";
        num=num%1000;
      }else if(num/100!=0){
        int tmp=num/100;
        if(tmp%5==4){
          if(tmp/5==0){
            str+="C";str+="D";
          }else{  
            str+="C";str+="M";
          }
        }else{
          if(tmp/5!=0){
            str+="D";
          }
          for(int i=0;i<tmp%5;i++) str+="C";
        }
        num=num%100;
      }else if(num/10!=0){
        int tmp=num/10;
        if(tmp%5==4){
          if(tmp/5==0){
            str+="X";str+="L";
          }else{
            str+="X";str+="C";
          }
        }else{
          if(tmp/5!=0){
            str+="L";
          }
          for(int i=0;i<tmp%5;i++) str+="X";
        }
        num=num%10;
      }else{
        if(num%5==4){
          if(num/5==0){
            str+="I";str+="V";
          }else{
            str+="I";str+="X";
          }
        }else{
          if(num/5!=0){
            str+="V";
          }
          for(int i=0;i<num%5;i++) str+="I";
        }
        num=num%1;
      }
    }
    return str;
  }
};

12. Integer to Roman(C++)

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