CryptoAPI與openssl RSA非對稱式加密解密(PKCS1 PADDING)互動

(以下代碼中都只做測試用,有些地方沒有釋放記憶體...這個自己解決下)

1.RSA非對稱的,首先提供一個供測試用的認證和私密金鑰的資料

1)pem格式的認證和私密金鑰(公私密金鑰是對應的)的base64編碼

void readPriKey(string &a){a =  "-----BEGIN RSA PRIVATE KEY-----\n";a.append("MIICXQIBAAKBgQDTFPiHkUX279j7OnK2ToLrwD/QI9N/fL/XoMnW1sBYJdSWs/VP\n");a.append("5oywvy6yJ0KMpfYcbRCJh2oRbPw7T9IrSHKdOkhB9PF6qwn90xb3Bk22l1LYZNfw\n");a.append("IQKqRjAXctR8GSC5ULBQmZK2T6m50oD5vl6rD6lnmrQyQSZ3tNNRYbxx/QIDAQAB\n");a.append("AoGAVqzSzOAzaY3dfHPorMGacvHzgiVj8IKqSAHHP8fZHZkTLXrh7ZhPBzjKFO+Y\n");a.append("HSb843lJhB+tx1AIVtaVB57tKLHJSrAjFem6mHV+X+JhMeX358QS0QFbUiKfAK5e\n");a.append("AkM1UdihF/3BX47DZUe44ntRqhffwsNGuZs2tB5FPHIpnGUCQQDvuBumamo+4tff\n");a.append("oF9Z/iuMJTyDerPgrQbC85ZoHBULLKtnzSUt7pdSsPMMBfImDpquhkLntC+kFV5b\n");a.append("yXu2nC5bAkEA4Wr1na+izFxmOnppvOjs7eFnch2THvNsajJ+Yl/jnRGGS5CLccrd\n");a.append("JgUm+j91VUitl88XY/GXAUDIobGw/iAAhwJBANZziODekD/D5cVcDhFPDZwpb7Jb\n");a.append("ofHcOJFNIv/uJ3FAu/J3lsw5hsxmGnhmFVOwevaoi9AG5RvQNgK9A9zAacMCQQDT\n");a.append("PI4qVHp0k2nhBvGra4MLcBymXXyOloJUCjlRKpZ7i/6TNULXQcl3ZYCfJXRolRDH\n");a.append("n/NFXxGoxPK+Q2ue2JJlAkBw1Z/1q2f6JYJ8pLBvdBSmOmKvm+O7x5s0csN7DnXf\n");a.append("aK1D4/cyCbLdqgogbolQkOwIwUuXLkitW1ldh+MinTMz\n");a.append("-----END RSA PRIVATE KEY-----\n");}void readCert(string &a){a = "-----BEGIN CERTIFICATE-----\n";a.append("MIIGVTCCBT2gAwIBAgIKGCyzsAAAAAAAbjANBgkqhkiG9w0BAQUFADA9MRUwEwYK\n");a.append("CZImiZPyLGQBGRYFbG9jYWwxEzARBgoJkiaJk/IsZAEZFgNpc3MxDzANBgNVBAMT\n");a.append("BldIVUlTUzAeFw0xMjA0MTEwMTMxNThaFw0xMzA0MTEwMTMxNThaMHIxFTATBgoJ\n");a.append("kiaJk/IsZAEZFgVsb2NhbDETMBEGCgmSJomT8ixkARkWA2lzczEOMAwGA1UEAxMF\n");a.append("VXNlcnMxEjAQBgNVBAMMCeWRqOe7jeemuTEgMB4GCSqGSIb3DQEJARYRemhvdXl1\n");a.append("emh5QDEyNi5jb20wgZ8wDQYJKoZIhvcNAQEBBQADgY0AMIGJAoGBANMU+IeRRfbv\n");a.append("2Ps6crZOguvAP9Aj0398v9egydbWwFgl1Jaz9U/mjLC/LrInQoyl9hxtEImHahFs\n");a.append("/DtP0itIcp06SEH08XqrCf3TFvcGTbaXUthk1/AhAqpGMBdy1HwZILlQsFCZkrZP\n");a.append("qbnSgPm+XqsPqWeatDJBJne001FhvHH9AgMBAAGjggOkMIIDoDAdBgNVHQ4EFgQU\n");a.append("vjfBpRVvsUsaWnX4dC81QzXu5T4wHwYDVR0jBBgwFoAU++PzmmgpwxErxTVrbJp5\n");a.append("IzqO3RswggECBgNVHR8EgfowgfcwgfSggfGgge6GgbNsZGFwOi8vL0NOPVdIVUlT\n");a.append("UyxDTj16c3ktMDIxMWMxNWEyNTIsQ049Q0RQLENOPVB1YmxpYyUyMEtleSUyMFNl\n");a.append("cnZpY2VzLENOPVNlcnZpY2VzLENOPUNvbmZpZ3VyYXRpb24sREM9aXNzLERDPWxv\n");a.append("Y2FsP2NlcnRpZmljYXRlUmV2b2NhdGlvbkxpc3Q/YmFzZT9vYmplY3RDbGFzcz1j\n");a.append("UkxEaXN0cmlidXRpb25Qb2ludIY2aHR0cDovL3pzeS0wMjExYzE1YTI1Mi5pc3Mu\n");a.append("bG9jYWwvQ2VydEVucm9sbC9XSFVJU1MuY3JsMIIBFgYIKwYBBQUHAQEEggEIMIIB\n");a.append("BDCBowYIKwYBBQUHMAKGgZZsZGFwOi8vL0NOPVdIVUlTUyxDTj1BSUEsQ049UHVi\n");a.append("bGljJTIwS2V5JTIwU2VydmljZXMsQ049U2VydmljZXMsQ049Q29uZmlndXJhdGlv\n");a.append("bixEQz1pc3MsREM9bG9jYWw/Y0FDZXJ0aWZpY2F0ZT9iYXNlP29iamVjdENsYXNz\n");a.append("PWNlcnRpZmljYXRpb25BdXRob3JpdHkwXAYIKwYBBQUHMAKGUGh0dHA6Ly96c3kt\n");a.append("MDIxMWMxNWEyNTIuaXNzLmxvY2FsL0NlcnRFbnJvbGwvenN5LTAyMTFjMTVhMjUy\n");a.append("Lmlzcy5sb2NhbF9XSFVJU1MuY3J0MAwGA1UdEwEB/wQCMAAwCwYDVR0PBAQDAgWg\n");a.append("MD4GCSsGAQQBgjcVBwQxMC8GJysGAQQBgjcVCIbd/wqC4JYWgbmLGoKIvT+HxNMh\n");a.append("gXGE+cJBg4yVdgIBZAIBBjApBgNVHSUEIjAgBggrBgEFBQcDAgYIKwYBBQUHAwQG\n");a.append("CisGAQQBgjcKAwQwNQYJKwYBBAGCNxUKBCgwJjAKBggrBgEFBQcDAjAKBggrBgEF\n");a.append("BQcDBDAMBgorBgEEAYI3CgMEMDsGA1UdEQQ0MDKgHQYKKwYBBAGCNxQCA6APDA16\n");a.append("c3lAaXNzLmxvY2FsgRF6aG91eXV6aHlAMTI2LmNvbTBEBgkqhkiG9w0BCQ8ENzA1\n");a.append("MA4GCCqGSIb3DQMCAgIAgDAOBggqhkiG9w0DBAICAIAwBwYFKw4DAgcwCgYIKoZI\n");a.append("hvcNAwcwDQYJKoZIhvcNAQEFBQADggEBABj0xXhayI5JdqbuyAbqNwzGZxt4X102\n");a.append("CFFeTU5jauspQjqEpar+/IQ+r3/vf162bY/lLHLpDarFLbZ9dAC6nqNfnE4gg9r7\n");a.append("p+dbkbzFyBuSTqrzHQ6JgRYSdjwaksHV+uZuP7dfP2HXw4F1T3Ch/7ZKW9+ZlVvd\n");a.append("QCygAu0z+TS2e7oRFb+swQLVKda8kPTM/b69+r/xdTHXY6+CkfVAk4oYBB56a9AD\n");a.append("t1XOoAUa42fJdit6+7ssLLTZkZLNsQl6qsuTdv64dIMda4C6NnUsKDfjWGa+0vs3\n");a.append("VjVNsUC5jo4qRc4XmBvJIx6e5M420sPj2Gi/+ssgmaXK+zUWzowIoMU=\n");a.append("-----END CERTIFICATE-----\n");}

2)CryptoAPI和openssl公私密金鑰保持一致,去掉pem頭尾直接用便是,沒有加密

  認證的:

void readCertBase64(string &a){a = "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\n";}

因為嘗試私密金鑰沒有匯入成功,暫且不管,關於這一點待會再說驗證互動成功的替換方案

2.先來看下openssl的RSA實現方案,openssl本身提供了許多的padding方式,

因為CryptoAPI只提供了PKCS1和OAEP兩種補齊方式,預設使用的PKCS1,那這裡就用PKCS1來驗證吧

1)首先需要匯入認證和私密金鑰,用於後續加密解密,這裡就直接採用通過Base64碼來匯入

EVP_PKEY * importKey(){OpenSSL_add_all_algorithms();EVP_PKEY *prikey;string a = "";readPriKey(a);//擷取私密金鑰的base64碼const char* sPriKey = a.c_str();BIO* bio = BIO_new_mem_buf((void*)sPriKey,strlen(sPriKey));//通過BIO放入記憶體prikey = PEM_read_bio_PrivateKey(bio,NULL,NULL,NULL);//讀取bio,擷取私密金鑰對象BYTE* sign_value = (BYTE*)malloc(1024);unsigned int len;return prikey;}EVP_PKEY * importCert(){X509* cert;OpenSSL_add_all_algorithms();string a = "";readCert(a);//認證的base64碼const char* sCert = a.c_str();BIO* bio = BIO_new_mem_buf((void*)sCert,strlen(sCert));//存到記憶體cert = PEM_read_bio_X509(bio,NULL,NULL,NULL);//讀取bio,擷取認證對象EVP_PKEY* evp_pubKey =X509_get_pubkey(cert);//擷取認證的公開金鑰int len;if(evp_pubKey){return evp_pubKey;}elsecout << "evp_pubKey == NULL" << endl;return NULL;}

2)有了公開金鑰,私密金鑰對象,接下來做非對稱式加密和解密就簡單些了

這裡得提下補齊方式,因為和CryptoAPI的補齊方式要保持一致,折騰了許多時間

CryptoAPI的預設補齊方式是PKCS1,我先以為就是NO_PADDING,結果發現CryptoAPI貌似就沒有對NO_PADDING的支援

openssl有NO_PADDING的支援,如果使用這個方式,最好自己將剩餘位全部補上規律的資料,便於解密後容易擷取到要的明文

NO_PADDING就必須明文和密鑰大小一樣了,1024位RSA對應128位元組明文

PKCS1的得減去11位元組儲存PKCS1自己的資料,1024位RSA只能加密117位元組明文

OAEP則得減去41位元組,只能加密87位元組明文

如果超過大小,當然可以自己去分節處理,這裡就不予討論了

void evelop(EVP_PKEY* evp_pubKey/*公開金鑰對象*/,BYTE** out/*加密結果*/,unsigned int &cOut/*加密結果大小*/,const BYTE* in/*明文*/,unsigned int cIn/*明文大小*/){OpenSSL_add_all_algorithms();bool hasErr = true;EVP_PKEY_CTX* ctx = EVP_PKEY_CTX_new(evp_pubKey,NULL);if(!ctx)goto err;if(EVP_PKEY_encrypt_init(ctx)<=0)goto err;if (EVP_PKEY_CTX_set_rsa_padding(ctx, RSA_PKCS1_PADDING) <= 0)//設定補齊方式goto err;if(EVP_PKEY_encrypt(ctx,NULL,&cOut,in,cIn)<=0)//得到加密的長度,一般都是跟密鑰一樣長,1024位的RSA密鑰就是128位元組goto err;*out =(BYTE*) OPENSSL_malloc(cOut);if(!out)goto err;if(EVP_PKEY_encrypt(ctx,*out,&cOut,in,cIn)<=0)//得到加密結果goto err;cout << "加密成功!" << endl;hasErr = false;err:EVP_PKEY_CTX_free(ctx);if(!hasErr)return;return;}void develop(EVP_PKEY* priKey,BYTE** out,unsigned int &cOut, BYTE* data,unsigned int cData){OpenSSL_add_all_algorithms();bool hasErr = true;EVP_PKEY_CTX* ctx = EVP_PKEY_CTX_new(priKey,NULL);if(!ctx)goto err;if (EVP_PKEY_decrypt_init(ctx) <= 0)goto err;if(EVP_PKEY_CTX_set_rsa_padding(ctx, RSA_PKCS1_PADDING) <= 0)//與加密同樣的PKCS1補齊goto err;if (EVP_PKEY_decrypt(ctx, NULL, &cOut, data, cData) <= 0)//解密結果大小goto err;*out =(BYTE*) OPENSSL_malloc(cOut);//分配記憶體if (!out)goto err;if (EVP_PKEY_decrypt(ctx, *out, &cOut, data, cData) <= 0)//得到解密結果goto err;hasErr = false;err://輸出一些錯誤資訊,偶爾錯誤資訊得不到,只得到一些檔案名稱和所在行,就跑到原始碼去找...麻煩死了,如果有好的方案求回複~EVP_PKEY_CTX_free(ctx);if(!hasErr)return;cout << "err in develop" << endl;const      char*file,*data1,*efunc,*elib,*ereason,*p;int                         line,flags;unsigned long  errn;errn=ERR_peek_error_line_data(&file,&line,&data1,&flags);printf("ERR_peek_error_line_data err : %ld,file :%s,line :%d,data :%s\n",errn,file,line,data1);}

3)自己測試下上面的代碼吧,應該是沒問題的

2.CryptoAPI的RSA非對稱式加密

1)首先依然是公私密金鑰資料問題

這裡先看下通過base64匯入認證吧,私密金鑰的問題放在第三部分再討論

PCCERT_CONTEXT  importCryptoCert(string base64Cert){PCCERT_CONTEXT  pCertContext = NULL; int len;BYTE* certEncoded = Base64::base64_decode(base64Cert,len);//BASE64解碼,很多方式,先前博文中有代碼if(pCertContext = CertCreateCertificateContext(X509_ASN_ENCODING | PKCS_7_ASN_ENCODING,              certEncoded,  len)) //直接就通過位元組數組匯入成認證內容物件了{printf("A new certificate has been created.\n");}else{printf("A new certificate could not be created.\n");}return pCertContext;}

2)公開金鑰加密,CryptoAPI的公開金鑰加密也做了一些封裝,沒注意到的話得折騰好長時間

我使用的CryptEncrypt,而加密結果是以 little-endian 
排列的位元組數組,openssl則與其相反

關於CryptoAPI的說明,remark最後一句話,很小的字....

void encryptByPubKey(HCRYPTPROV hProv,PCCERT_CONTEXT cert,BYTE* text,unsigned long &len){HCRYPTKEY hKey;CERT_PUBLIC_KEY_INFO pubKeyInfo = cert->pCertInfo->SubjectPublicKeyInfo;//拿到公開金鑰資訊if(!CryptImportPublicKeyInfoEx(hProv,X509_ASN_ENCODING,&pubKeyInfo,CALG_RSA_KEYX,0,NULL,&hKey))//匯入,擷取公開金鑰對象{printf("CryptImportPublicKeyInfoEx error:0X%x.\n",GetLastError());return;}if(!CryptEncrypt(hKey,NULL,true,0,text,&len,128))//加密,padding參數為0,預設就是PKCS1的,不用管了,最後一個參數為128,是對於1024位RSA密鑰,明文text得分配128個位元組{printf("CryptEncrypt error:0X%x.\n",GetLastError());return;}//以下將密文倒序,如果你在openssl倒序了,那這裡就不用了,反正CryptoAPI和openssl本身的相片順序就是反的for(int i = 0 ; i < len / 2;i++){BYTE temp = text[i];text[i] = text[len - i - 1];text[len - i - 1] = temp;}printByte(text,len);}

3)試下這個部分的加密吧,能夠被openssl解密就沒問題了

3.以上只試了CryptoAPI加密openssl解密,因為私密金鑰沒匯入成功的關係,也沒時間再去嘗試了,暫且換一種替代方案來測試

如果CryptoAPI解密了CryptoAPI加密的,那這個也是等價的,那乾脆直接從windows密鑰庫擷取公私密金鑰,用CryptoAPI直接做加密解密

從windows庫擷取認證就不在這討論了,看下私密金鑰解密的部分

void decryptByPriKey(PCCERT_CONTEXT cert,BYTE* encText,unsigned long len){//將結果再反序一次,用於CryptoAPI自己解密for(int i = 0 ; i < len / 2;i++){BYTE temp = encText[i];encText[i] = encText[len - i - 1];encText[len - i - 1] = temp;}HCRYPTPROV_OR_NCRYPT_KEY_HANDLE hKeyProv;DWORD *dwKeyType;BOOL bFreeKeyProv = FALSE;  if(!CryptAcquireCertificatePrivateKey(cert, 0, 0, &hKeyProv, dwKeyType, &bFreeKeyProv))  //擷取認證對應的私密金鑰控制代碼{  printf("CryptAcquireCertificatePrivateKey error:0X%x.\n",GetLastError());return;} HCRYPTKEY hKey;if(!CryptGetUserKey(hKeyProv,AT_KEYEXCHANGE,&hKey))//通過控制代碼擷取私密金鑰對象{printf("CryptGetUserKey error:0X%x.\n",GetLastError());return;}if(!CryptDecrypt(hKey,NULL,true,0,encText,&len)){//解密,也可以把padding參數換成CRYPT_DECRYPT_RSA_NO_PADDING_CHECKprintf("CryptDecrypt error:0X%x.\n",GetLastError());return;}printByte(encText,len);}

如果到此都沒有什麼問題,整個互動就算完成了.

前一篇提了AES的,還差一個簽名的下回再來討論了