javascript 瀏覽器判斷 綁定事件 arguments 轉換數組 數組遍曆

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上載者:User

複製代碼 代碼如下:var $d = document;

function $i(s){return $d.getElementById(s);}
var _jsc={}
_jsc.client=(function(){
var t={};
var b=navigator.userAgent.toLowerCase();
t.isOpera=(b.indexOf('opera')>-1)
t.isIE=(b.indexOf('msie')>-1)
t.isFF=(!t.isOpera&&!t.isIE&&b.indexOf("firefox")>-1);
return t;

})()
_jsc.util=(function(){
var t={}
t.addEvent=function(o,e,f){
if(_jsc.client.isIE){
o.attachEvent("on"+e,f)
}else{
o.addEventListener(e,f,fasle);
}
return true
}
return t;
})();
//window.onload=function(){_jsc.util.addEvent(document,"click",showMsg("z","d"))}
_jsc.util.addEvent(document,"click",function(){showMsg("a","b")})

function showMsg()
{
//alert(typeof arguments)
//var dd=[arguments[0],arguments[1]]
//var o = {a:'aa', b:'bb', c:'cc'};
//var o = {};
o=arguments
o=Array.prototype.slice.call(arguments,0);
for(var p in o)
{
alert(o[p]);
}

迴圈對象的所有屬性:
<script>
var o = {a:'aa', b:'bb', c:'cc'};
for(var p in o)
{
alert(eval("o." + p));
}
</script>

迴圈數組的所有元素:

<script>
var arr = ['11', '22', '33'];
for(var i in arr)
{
alert(arr[i]);
}
</script>

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