javascript–求數組的最大最小值

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<script type="text/javascript">var arr=[21,2,34,22,5,7,23,63,212,324,56,6,8,32,12,34,2,334344,22,5,7,23,63,212,324,56,6,123,345,1233,56,127,84,123,13,344,324,12,5,1,6,1,7,2,123,6512,323,97,434];//數組按從大到小排序arr.sort(function(a,b){return b-a;});  //求數組中最大值,最小值// 方法一Array.prototype.max=function(){ var r=this.sort(function(a,b){return a-b;}) return r[r.length-1]; }Array.prototype.min=function(){ var r=this.sort(function(a,b){return a-b;}) return r[0]; }// 方法二Array.prototype.max=function(){ var max = this[0];    var len = this.length;     for (var i = 1; i < len; i++){     if (this[i] > max) {        max = this[i];     }     }     return max; } Array.prototype.min = function() {    var min = this[0];    var len = this.length;    for (var i = 1; i < len; i++){        if (this[i] < min){             min = this[i];                }         }     return min;   }    //方法三Array.prototype.max = function(){      return Math.max.apply({},this);}  Array.prototype.min = function(){      return Math.min.apply({},this)}    console.time("aa");  var maxNum=arr.max();console.timeEnd("aa");alert(maxNum);</script>
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