javascript 學習筆記(四) 倒計時程式碼

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首先看全部完整代碼:
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta content="text/html; charset=utf-8" http-equiv="Content-Type" /> <title>countDown test</title> </head> <body> <p> <label for="deadline">到期日</label> <input type="text" value="2011-06-11" id="deadline" /> <input type="button" value="開始倒計時" onclick="window.setInterval('countDown(\'deadline\')', 1000)" /></p> <p id="showTime"></p> </body> </html>
[Ctrl+A 全選 注:如需引入外部Js需重新整理才能執行]
html部分代碼:
可在文字框中輸入倒計時的時間,如果目前時間小於截止時間,則正常返回,反之,則返回距離到期日到現在的時間
複製代碼 代碼如下:
<p>
<label for="deadline">到期日</label>
<input type="text" value="2011-06-11" id="deadline" />
<input type="button" value="開始倒計時" onclick="window.setInterval('countDown(\'deadline\')', 1000)" />
</p>
<p id="showTime"></p>

javascript部分代碼:
複製代碼 代碼如下:
function countDown(endDate) {
var now = new Date();
var deadtime = document.getElementById(endDate);
var deadline = new Date(deadtime.value);
//本地時間與格林威治標準時間 (GMT) 的分鐘差
var timeDiff = now.getTimezoneOffset();
//此處有些不解,如果把分鐘差轉化成毫秒應該是timeDiff*60*1000,但是這樣返回的資料不正確!
var leave = Math.abs(deadline.getTime() - now.getTime() + timeDiff*60);
var minute = 1000 * 60;
var hour = minute * 60;
var day = hour * 24;
var countDay = Math.floor(leave/day);
//var countHour = Math.floor((leave - day*countDay)/hour); 兩種計算思路
var countHour = Math.floor(leave/hour - countDay*24);
var countMinute = Math.floor(leave/minute) - countDay*24*60 - countHour*60;
var countSecond = Math.floor(leave/1000) - countDay*24*60*60 - countHour*60*60 - countMinute*60;
var outStr = "";
if(deadline < now) {
outStr = "距離"+deadtime.value+"已有"+countDay+"天"+countHour+"小時"+countMinute+"分"+countSecond+"秒";
} else {
outStr = "距離"+deadtime.value+"還差"+countDay+"天"+countHour+"小時"+countMinute+"分"+countSecond+"秒";
}
var showTime = document.getElementById("showTime");
showTime.innerHTML = outStr;
}

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