javascript 返回數組中不重複的元素

標籤：

這是實現結構偽類type-of-type的部分代碼： 

<script type="text/javascript">
var ret= ["span","span","strong","span","b"]
var norepeat = function(array){
var set = array.join(",")+",";
while(array.length){
var el = array.shift();
set = set.replace(el+",","");
if(set.indexOf(el+",") != -1){
set = set.replace(new RegExp(el+",","g"),"");
array = set.replace(/,$/g,"").split(",");
}else{
set = el+","+set;
}
}
return set.replace(/,$/g,"").split(",")
}
alert(norepeat(ret))//最後返回b,strong
</script>

覺得效果不高，向無憂高手求救。下面是客服果果的(好強大的正則替換啊)： 

<script language="javascript">
var ret= ["span","span","strong","span","b"];
var norepeat=function (x) {
var y=‘c0cb5f0fcf239ab3d9c1fcd31fff1efc‘;
return x.sort().join(y).replace(RegExp(‘(.*(‘+y+‘|$))\\1+‘,‘g‘),‘‘).split(y);
};
alert(norepeat(ret));
</script>

abcdreamer 的實現（此實現能過濾非純字串數組裡的重複，我比較喜歡）：

<script language="javascript">
var a = ["span","span","strong","span","b"];
function norepeat(a) {
var i = a.length, j, b;
while (i--) {
j = i;
b = false;
while (j--) {
if (a[i] === a[j]) {
a.splice(j, 1);
i--;
b = true;
}
}
if (b) a.splice(i, 1);
}
return a;
}
alert(norepeat(a));
</script>

哪位高手有更好的實現，請告訴我一聲！ 
看來有些人不明白norepeat函數與unique函數的區別，norepeat是去除數組中重複的元素，如果數組中有兩個a，則去除這兩個，unique則會去除其中之一。下面是unique函數的實現： 

<script language="javascript">
Array.prototype.inArray = function(el){
for (var i=0,n=this.length;i<n;i++ )
if(this[i]===el)return true;
return false;
}
Array.prototype.unique = function() {
var i = 0, n = this.length,ret = [];
for (; i < n; i++)
if (!ret.inArray(this[i])) ret.push(this[i]);
return ret;
};
var ret= ["span","span","strong","span","b"]
alert(ret.unique()) //返回"span","strong","b"
</script>

javascript 返回數組中不重複的元素