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這種做法是錯的，因為javascript分原始類型與參考型別（與java、c#類似）。Array是引用類
型。array2得到的是引用，所以對array1的修改會影響到array2。
二、 使用slice()
可使用slice()進行複製，因為slice()返回也是數組。 複製代碼 代碼如下:var array1 = new Array("1","2","3");
var array2;
array2 = array1.slice(0);
array1.length = 0;
alert(array2); //返回1、2、3
三、 使用concat()
注意concat()返回的並不是調用函數的Array，而是一個新的Array，所以可以利用這一點進行複製。 複製代碼 代碼如下:var array1 = new Array("1","2","3");
var array2;
array2 = array1.concat();
array1.length = 0;
alert(array2); //返回1、2、3
四、 測試 複製代碼 代碼如下:<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01//EN" "http://www.w3.org/TR/html4/strict.dtd">
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8">
<title>Array Test</title>
<script type="text/javascript">
var array1;
var array2;
function clone1() {
array1 = new Array("1","2","3");
array2 = array1;
array1.length = 0;
alert(array2);
}
function clone2() {
array1 = new Array("1","2","3");
array2 = array1.slice(0);
array1.length = 0;
alert(array2);
}
function clone3() {
array1 = new Array("1","2","3");
array2 = array1.concat();
array1.length = 0;
alert(array2);
}
</script>
</head>
<body>
<input type="button" value="clone1" onclick="clone1()" /><br />
<input type="button" value="clone2" onclick="clone2()" /><br />
<input type="button" value="clone3" onclick="clone3()" /><br />
</body>
</html>
在IE8及FF3.0下均通過測試
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