Jquery submit()無法提交問題

來源:互聯網
上載者:User

複製代碼 代碼如下:
<form action="register.php" method="post">
<div class="loginform_row">
<label>使用者名稱:</label>
<input type="text" class="loginform_input" id="name" name="name" /><div id="nameerror"></div>
</div>
<div class="loginform_row">
<label>密碼:</label>
<input type="text" class="loginform_input" id="pass" name="pass" /><div id="passerror"></div>
</div>
<div class="loginform_row">
<label>郵箱:</label>
<input type="text" class="loginform_input" id="email" name="email" /><div id="emailerror"></div>
</div>
<div class="loginform_row">
<input type="button" class="loginform_submit" id="submit" value="註冊" />改為<input type="button" class="loginform_submit" id="register" value="註冊" />
</div>
<div class="clear"></div>
</form>
$("#submit").click(function() {
$("form").submit();
});

上述代碼點擊註冊按鈕時無法提交表單

原因
Additional Notes:
Forms and their child elements should not use input names or ids that conflict with properties of a form, such as submit, length, or method. Name conflicts can cause confusing failures. For a complete list of rules and to check your markup for these problems, see DOMLint.

其他注意事項
表單和其子項目不宜用一個表單的屬性的屬性作為name或id的名稱,如submit, length, or method,是、會產生衝突。名稱衝突可能會導致混亂的失敗。對於一個完整的規則列表,並檢查這些問題標記,看DOMLint。
所以將註冊按鈕的id改為“register”就OK了

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