oracle中lead和lag函數 (轉載)

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這兩個函數,是位移量函數,其用途是:可以查出同一欄位下一個值或上一個值。
lead(col_name,num,flag)col_name是列名;num是取向下第幾個值;flag是一個標誌,也就是如果向下第幾個值是空值的話就取flag;例如lead(login_time,1,null)這個是向下取一個值,如果這個值為空白則按空算,當然也可以用其他值替換。lag(col_name,num,flag)和lead類似,col_name是列名;num是取向上第幾個值;flag是一個標誌,也就是如果向上第幾個值是空值的話就取flag;例如lag(login_time,1,null)這個是向上取一個值,如果這個值為空白則按空算,當然也可以用其他值替換。
舉個例子:有一個表tmp_test(u_id,login_time)查一下這個表中連續7天都有登入機器的人是誰?造下資料:create table tmp_test(u_id number,login_time date);
insert into tmp_testselect 1 rn,sysdate + rownum as login_timefrom dualconnect by level <=8unionselect 2 rn,sysdate + rownum as login_timefrom dualconnect by level <=3unionselect 3 rn,sysdate + rownum as login_timefrom dualconnect by level <=2unionselect 2 rn,sysdate + rownum+4 as login_timefrom dualconnect by level <=5;commit;
然後造幾條重複資料:insert into tmp_testselect 1 rn,sysdate + rownum as login_timefrom dualconnect by level <=3;
查下資料:select * from tmp_test; U_ID LOGIN_TIME---------- ----------- 1 2012/3/8 6:33:24 1 2012/3/9 6:33:24 1 2012/3/10 6:33:24 1 2012/3/11 6:33:24 1 2012/3/12 6:33:24 1 2012/3/13 6:33:24 1 2012/3/14 6:33:24 1 2012/3/15 6:33:24 2 2012/3/8 6:33:24 2 2012/3/9 6:33:24 2 2012/3/10 6:33:24 2 2012/3/12 6:33:24 2 2012/3/13 6:33:24 2 2012/3/14 6:33:24 2 2012/3/15 6:33:24 2 2012/3/16 6:33:24 3 2012/3/8 6:33:24 3 2012/3/9 6:33:24 1 2012/3/8 6:37:35 1 2012/3/9 6:37:35 1 2012/3/10 6:37:35
從上面資料看出其實只有u_id=1滿足條件,那麼怎麼用sql實現呢?SQL> select distinct u_id 2 from (select u_id, 3 login_time last_login_time, 4 lead(login_time, 6) over(partition by u_id order by u_id, login_time) next_login_time 5 from (select distinct u_id, trunc(login_time) login_time 6 from tmp_test)) 7 where next_login_time - last_login_time = 6; U_ID---------- 1
ok,就是這個結果。其實用lag也可以實現相同結果,寫法如下:
select distinct u_id from (select u_id, login_time last_login_time, lag(login_time, 6) over(partition by u_id order by u_id, login_time) next_login_time from (select distinct u_id, trunc(login_time) login_time from tmp_test)) where last_login_time - next_login_time = 6;
   

oracle中lead和lag函數 (轉載)

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