學點 C 語言(25): 資料類型 – 結構數組與結構指標

1. 結構數組:

#include <stdio.h>int main(void){    struct Rec {int x,y;};    struct Rec rs[10];        size_t i;    for (i = 0; i 

#include <stdio.h>int main(void){    struct Rec {        char  name[12];        short age;    } rs[3] = {                {"AAA", 11},                {"BBB", 22},                {"CCC", 22}              };     size_t i;    for (i = 0; i 

2. 結構指標指向已存在的結構數組:

#include <stdio.h>int main(void){    struct Rec {        char  name[12];        short age;    } rs[3] = {                {"AAA", 11},                {"BBB", 22},                {"CCC", 22}              };    struct Rec *p = rs;     printf("%s, %d\n", p->name, p->age);    printf("%s, %d\n", (p+1)->name, (p+1)->age);    printf("%s, %d\n", (p+2)->name, (p+2)->age);        getchar();    return 0;}

3. 結構指標(單個結構):

#include <stdio.h>#include <stdlib.h>#include <string.h>int main(void){    struct Rec {        char  name[12];        short age;    };    struct Rec *p = NULL;     p = (struct Rec *)malloc(sizeof(struct Rec));    stpcpy(p->name, "ABC");    p->age = 99;    printf("%s, %d\n", p->name, p->age);    printf("%s, %d\n", (*p).name, (*p).age);    free(p);             getchar();    return 0;}

4. 結構指標(多個結構):

#include <stdio.h>#include <stdlib.h>int main(void){    struct Rec {        int x;        int y;    } *p;    size_t i, count = 10;    p = (struct Rec *)malloc(sizeof(struct Rec)*count);    for (i = 0; i x = i;        (p+i)->y = i * i;    }    for (i = 0; i x, (p+i)->y);        }    free(p);             getchar();    return 0;}

5. 連續的多個結構不就是結構數組了嗎?(同上例)

#include <stdio.h>#include <stdlib.h>int main(void){    struct Rec {        int x;        int y;    } *p;    size_t i, count = 10;    p = (struct Rec *)malloc(sizeof(struct Rec)*count);    for (i = 0; i