標籤:
Write an algorithm to determine if a number is "happy".
A happy number is a number defined by the following process: Starting with any positive integer, replace the number by the sum of the squares of its digits, and repeat the process until the number equals 1 (where it will stay), or it loops endlessly in a cycle which does not include 1. Those numbers for which this process ends in 1 are happy numbers.
Example: 19 is a happy number
- 12 + 92 = 82
- 82 + 22 = 68
- 62 + 82 = 100
- 12 + 02 + 02 = 1
個人感覺這道題重點在於,我們用loop迴圈來計算這個數是不是happy number(計算方法很簡單)
但是如果這個數不是Happy Number,怎樣才能讓這個loop停止呢。
這裡就可以用到HashSet,當n在計算過程中出現重複的值時,就證明這個數已經不可能是happy number了,我們的loop可以停止了。
用hashset裡面的contains()method來判斷。(記得add()method一定要放在前面不要末尾哦)n的值也要隨時更新。
代碼如下。~
public class Solution { public boolean isHappy(int n) { if(n==1) return true; if(n<=0) return false; int result=0; HashSet<Integer> hash=new HashSet<Integer>(); while(!hash.contains(n)){ result=0; hash.add(n); while(n!=0){ int temp=n%10; result=result+temp*temp; n=n/10; } n=result; if(n==1){ return true; } } return false; }}
[LeetCod] Happy Number