標籤:arrays
題目如下:
Given numRows, generate the first numRows of Pascal‘s triangle.
For example, given numRows = 5,
Return
[
[1],
[1,1],
[1,2,1],
[1,3,3,1],
[1,4,6,4,1]
]
My Code:
// 225mspublic class Solution { public List<List<Integer>> generate(int numRows) { //ERROR1: List is abstract; cannot be instantiated //List<List<Integer>> lists = new List<List<Integer>> (); //ERROR2: fail to ensure type safe //http://stackoverflow.com/questions/5763750/why-we-cant-do-listparent-mylist-arraylistchild //List<List<Integer>> lists = new ArrayList<List<Integer>> (); List<List<Integer>> lists = new ArrayList<ArrayList<Integer>> (); if (numRows <= 0) return lists; List<Integer> list1 = new ArrayList<Integer> (); list1.add(1); lists.add(list1); if (numRows == 1) return lists; List<Integer> oldList = null; for (int i = 2; i <=numRows; ++i) { List<Integer> newList = new ArrayList<Integer> (); newList.add(1); newList.add(1); for (int j = 1; j < i - 1; ++j) { newList.add(j, oldList.get(j) + oldList.get(j - 1)); } lists.add(newList); oldList = newList; } return lists; }}
小結分析:
1 上面的兩個錯誤,也是我正好不懂的關於java的文法的部分。
第一個錯誤,很好理解,抽象基類無法進行new的操作。
第二個錯誤,比較好玩, 搜到一個解釋,是這樣的:
假設這個寫法沒有錯誤,那麼可以寫成類似下面這個例子這樣的寫法:
ArrayList<Banana> bananas = new ArrayList<Banana>();List<Fruit> fruit = bananas;fruit.add(new Apple());Banana banana = bananas.get(0); //ERROR! not type safe<span style="white-space:pre"></span>
這將明顯是危險。That‘s clearly not type safe - you‘ve ended up with an apple in the collection of bananas.
LeetCode(118) Pascal's Triangle (Java)