LeetCode Happy Number

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Write an algorithm to determine if a number is "happy".

A happy number is a number defined by the following process: Starting with any positive integer, replace the number by the sum of the squares of its digits, and repeat the process until the number equals 1 (where it will stay), or it loops endlessly in a cycle which does not include 1. Those numbers for which this process ends in 1 are happy numbers.

Example: 19 is a happy number

  • 12 + 92 = 82
  • 82 + 22 = 68
  • 62 + 82 = 100
  • 12 + 02 + 02 = 1

思路分析:這題比較簡單,就是不斷的做各個位置數位平方加和操作,看是否會產生1。但是有一個地方要注意,就是怎麼判斷出現了迴圈,這裡定義了一個Set,儲存所有出現過的數字,對於計算得到的新的和,如果沒有在Set中出現,就添加到Set中繼續進行平方求和;否則,就是遇到了已經出現的數字,出現了迴圈,可以直接結束迴圈,返回false。

AC Code

public class Solution {public boolean isHappy(int n) {    HashSet<Integer> appearedNums = new HashSet<Integer>();    while(!appearedNums.contains(n)){        appearedNums.add(n);        int sum = 0;        while(n != 0){            int digit = n % 10;            n /= 10;            sum += Math.pow(digit,2);        }        n = sum;        if(sum == 1) return true;    }    return false;    }}


LeetCode Happy Number

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