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題目連結
題目要求:
Write an algorithm to determine if a number is "happy".
A happy number is a number defined by the following process: Starting with any positive integer, replace the number by the sum of the squares of its digits, and repeat the process until the number equals 1 (where it will stay), or it loops endlessly in a cycle which does not include 1. Those numbers for which this process ends in 1 are happy numbers.
Example: 19 is a happy number
- 12 + 92 = 82
- 82 + 22 = 68
- 62 + 82 = 100
- 12 + 02 + 02 = 1
Credits:
Special thanks to @mithmatt and @ts for adding this problem and creating all test cases.
這道題比較需要注意的一點是要在合適的時候跳出死迴圈。程式如下:
1 class Solution { 2 public: 3 bool isHappy(int n) { 4 vector<int> vec; 5 vec.push_back(n); 6 while(n!= 1) 7 { 8 int sum = 0; 9 int tmpN = n;10 while(tmpN != 0)11 {12 sum += (tmpN % 10) * (tmpN % 10);13 tmpN /= 10;14 }15 n = sum;16 17 if(find(vec.begin(), vec.end(), n) != vec.end())18 break;19 else20 vec.push_back(n);21 }22 23 return n == 1;24 }25 };
LeetCode之“數學”:Happy Number