Merge Intervals
Given a collection of intervals, merge all overlapping intervals.
For example,
Given [1,3],[2,6],[8,10],[15,18]
,
return [1,6],[8,10],[15,18]
.
/** * Definition for an interval. * struct Interval { * int start; * int end; * Interval() : start(0), end(0) {} * Interval(int s, int e) : start(s), end(e) {} * }; */class Solution {public: struct cmp{ bool operator()(const Interval& x, const Interval& y) const { if(x.start != y.start) return x.start < y.start; else return x.end < y.end; } }; vector<Interval> merge(vector<Interval> &intervals) { vector<Interval> result; if(intervals.empty())return result; sort(intervals.begin(), intervals.end(),cmp()); Interval cur = intervals[0]; for(int i=1;i<intervals.size();i++) { if(cur.end < intervals[i].start) { result.push_back(cur); cur = intervals[i]; }else{ cur.end = max(cur.end,intervals[i].end); } } result.push_back(cur); return result; }};