Leetcode: Spiral Matrix

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上載者:User

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void printacircle(vector<vector<int> > &matrix, vector<int> &path, int num)    {    int row = matrix.size();int col = matrix[0].size();for(int i = num; i < col-num; i++)path.push_back(matrix[num][i]);if( 2*num+2 <= row)for(int i = num+1; i < row-num; i++)path.push_back(matrix[i][col-num-1]);if(2*num+2<= col && 2*num+2 <= row)for(int i = col-2-num; i >= num; i--)path.push_back(matrix[row-1-num][i]);if( 2*num+3 <= row && 2*num+2 <= col)for(int i = row-2-num; i >= num+1; i--)path.push_back(matrix[i][num]);}vector<int> spiralOrder(vector<vector<int> > &matrix) {        // Start typing your C/C++ solution below        // DO NOT write int main() function        vector<int> path;        int row = matrix.size();        if(row<1)return path;        int col = matrix[0].size();for(int i = 0; i< (row+1)/2 && i < (col+1)/2; ++i)printacircle(matrix, path, i);    }


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