【LeetCode with Python】 Spiral Matrix II__Python

來源:互聯網
上載者:User
部落格網域名稱: http://www.xnerv.wang
原題頁面: https://oj.leetcode.com/problems/spiral-matrix-ii/
題目類型:
難度評價:★
本文地址: http://blog.csdn.net/nerv3x3/article/details/41628823

Given an integer n, generate a square matrix filled with elements from 1 ton2 in spiral order.

For example,
Given n = 3, You should return the following matrix:

[ [ 1, 2, 3 ], [ 8, 9, 4 ], [ 7, 6, 5 ]]

評論

class Solution:    # @return a list of lists of integer    def generateMatrix(self, n):        if 0 == n:            return [ ]        m = n        index = 1        matrix = [[0 for x in range(0, n)] for y in range(0, n)]        round = (n + 1) / 2        for x in range(0, round):            for y in range(x, n - x):                matrix[x][y] = index                index += 1            for y in range(x + 1, m - x - 1):                matrix[y][n - x - 1] = index                index += 1            if m - 2 * x > 1:  ###                for y in range(n - x - 1, x - 1, -1):                    matrix[m - x - 1][y] = index                    index += 1            if n - 2 * x > 1:      ###                for y in range(m - x - 2, x, -1):   ###                    matrix[y][x] = index                    index += 1        return matrix

聯繫我們

該頁面正文內容均來源於網絡整理,並不代表阿里雲官方的觀點,該頁面所提到的產品和服務也與阿里云無關,如果該頁面內容對您造成了困擾,歡迎寫郵件給我們,收到郵件我們將在5個工作日內處理。

如果您發現本社區中有涉嫌抄襲的內容,歡迎發送郵件至: info-contact@alibabacloud.com 進行舉報並提供相關證據,工作人員會在 5 個工作天內聯絡您,一經查實,本站將立刻刪除涉嫌侵權內容。

A Free Trial That Lets You Build Big!

Start building with 50+ products and up to 12 months usage for Elastic Compute Service

  • Sales Support

    1 on 1 presale consultation

  • After-Sales Support

    24/7 Technical Support 6 Free Tickets per Quarter Faster Response

  • Alibaba Cloud offers highly flexible support services tailored to meet your exact needs.