標籤:
Problem:
Evaluate the value of an arithmetic expression in Reverse Polish Notation.
Valid operators are +, -, *, /. Each operand may be an integer or another expression.
Some examples:
["2", "1", "+", "3", "*"] -> ((2 + 1) * 3) -> 9 ["4", "13", "5", "/", "+"] -> (4 + (13 / 5)) -> 6
Analysis:
Reference: https://en.wikipedia.org/wiki/Reverse_Polish_notationAfter reading the wiki page of the RPN, you could find out this problem is super easy!!!!But I still stupidly make A mistake!!!-----------------------------------------------------------------------------------------Mistake 1:Forget to take care of the order, when numbers were poped out from stack. |num2||num1|Note: num2 was poped before num1!!!For an oprand (+,-,*,/), we hope num1 (operand) num2I ingore the order at first, thus I have implemented following wrong codes:if (token.equals("+") || token.equals("-") || token.equals("*") || token.equals("/")) { int num1 = Integer.valueOf(stack.pop()); int num2 = Integer.valueOf(stack.pop()); int num3 = compute(num1, num2, token); ...}And it results in following error:Input:["4","3","-"]Output:-1Expected:Fix:if (token.equals("+") || token.equals("-") || token.equals("*") || token.equals("/")) { int num1 = Integer.valueOf(stack.pop()); int num2 = Integer.valueOf(stack.pop()); int num3 = compute(num2, num1, token); ...}
Solution:
public class Solution { public int evalRPN(String[] tokens) { if (tokens == null) throw new IllegalArgumentException("The passed in tokens array in null"); if (tokens.length == 0) return 0; Stack<Integer> stack = new Stack<Integer> (); for (String token : tokens) { if (token.equals("+") || token.equals("-") || token.equals("*") || token.equals("/")) { int num1 = Integer.valueOf(stack.pop()); int num2 = Integer.valueOf(stack.pop()); int num3 = compute(num2, num1, token); stack.push(num3); } else{ int num = Integer.valueOf(token); stack.push(num); } } return stack.pop(); } private int compute(int num1, int num2, String token) { int res = 0; switch (token) { case "+" : res = num1 + num2; break; case "-" : res = num1 - num2; break; case "*" : res = num1 * num2; break; case "/" : res = num1 / num2; break; } return res; }}
[LeetCode#150]Evaluate Reverse Polish Notation