List<string[]> 如何去重

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深度拷貝 List<string[]> 到一個新的List<string[]> 中（tempList），

遍曆tempList，移除原list中重複的string[],代碼如下:

static void Main(string[] args)        {            List<string[]> list = new List<string[]>();            list.Add(new string[]{"1","2","3"});            list.Add(new string[] { "1","2" ,"3"});            list.Add(new string[] { "1" });            list.Add(new string[] { "1" });            list.Add(new string[] { "1" });            var tempList = new List<string[]>(list);            if (list.Count >= 2)  //確保下標i不越界            {                for (int i = 1; i < tempList.Count; i++)                {                    if (string.Join(",", tempList[i]) == string.Join(",", tempList[i - 1]))                    {                        list.Remove(tempList[i]);                    }                }            }            foreach (var item in list)            {                string s = string.Join(",", item);                Console.WriteLine(s);            }            Console.ReadKey();        }

運行如下：

 

 

那麼問題又來了，挖掘機技術……呸！ 如果是List<List<string[]>>的集合又該如何去重呢？

原理是一樣的把List<string[]>變成字串，裝到List<string>中，根據List<sting>重複的元素的下標索引，刪除原集合中重複的元素，

代碼如下:

 static void Main(string[] args)        {            List<string[]> list = new List<string[]>();            list.Add(new string[]{"1","2","3"});            list.Add(new string[] { "1","2" ,"3"});            list.Add(new string[] { "1" });            list.Add(new string[] { "1" });            list.Add(new string[] { "1" });            List<string[]> list2 = new List<string[]>();            list2.Add(new string[] { "1", "2", "3" });            list2.Add(new string[] { "1", "2", "3" });            list2.Add(new string[] { "1" });            list2.Add(new string[] { "1" });            list2.Add(new string[] { "1" });            List<string[]> list3 = new List<string[]>();            list3.Add(new string[] { "1", "2", "3" ,"4","5"});            list3.Add(new string[] { "1", "2", "3" });            list3.Add(new string[] { "1" });            list3.Add(new string[] { "1" });            list3.Add(new string[] { "1" });            List<List<string[]>> superList = new List<List<string[]>>();            //集合list和集合list2是相同的            superList.Add(list);            superList.Add(list2);            superList.Add(list3);            List<string> strList = new List<string>();            foreach (var d in superList)            {                StringBuilder sb = new StringBuilder();                foreach (var dd in d)                {                    string s = string.Join(",", dd);                    sb.Append(s);                }                string str = sb.ToString();                strList.Add(str); //把superList中每個子項目拼接成一條字串放到strList中            }            if (strList.Count >= 2)            {                for (int i = 1; i < strList.Count; i++)                {                    if (strList[i] == strList[i - 1])                    {                        superList.RemoveAt(i);//根據strList中重複的字串的下標索引，刪除superList中的元素                    }                }            }            Console.WriteLine(superList.Count());            Console.ReadKey();        }

View Code

 

運行如下:

 

List<string[]> 如何去重