Minimum Window Substring

標籤：c   style   class   blog   code   java   

Given a string S and a string T, find the minimum window in S which will contain all the characters in T in complexity O(n).

For example,
S = "ADOBECODEBANC"
T = "ABC"

Minimum window is "BANC".

Note:
If there is no such window in S that covers all characters in T, return the emtpy string "".

If there are multiple such windows, you are guaranteed that there will always be only one unique minimum window in S.

class Solution {
private:
    int hashs[256];
    int hasht[256];
    inline bool check()
    {
        for(int i=0;i<256;i++)
            if(hashs[i]<hasht[i]) return false;
        return true;
    }
public:
    string minWindow(string S, string T) 
    {        
        for(int i=0;i<256;i++)
        {
            hashs[i]=0;                
            hasht[i]=0;
        }

        for(int i=0;i<T.size();i++)        
            hasht[T[i]]++;
                    
        int minl=-1;
        int minr=S.length();
                
        for(int i=0;i<S.size();i++)        
            hashs[S[i]]++;

        if(!check()) return "";
        
        int l=0;
        int r=0;

        for(int i=0;i<256;i++) hashs[i]=0;
        hashs[S[0]]=1;
        while(true)
        {
            if(check())
            {
                if(r-l<minr-minl)
                {
                    minl=l;
                    minr=r;
                    if(minr-minl+1==T.length()) break;
                }
                
                hashs[S[l]]--;
                l++;
            }
            else
            {
                r++;
                if(r==S.length()) break;
                hashs[S[r]]++;
            }
        }
        if(minl==-1) return "";
        else return S.substr(minl,minr-minl+1);
    }
};