$a=array(0 =>array([logo] => Array
(
[id] =>1
[sid] => 6
)
1=>array([logo] => Array
(
[id] =>2
[sid] => 6
)
)
使用foreach迴圈$a,只顯示不同的SID;
回複討論(解決方案)
貼出經var_export() 運行後的數組出來
$last = 0;foreach($a as $r) { foreach($r as $v) { if($last != $v['sid']) echo $v['sid']; $last = $v['sid']; }}
array ( 0 => array ( 'logo' => array ( 'id' => 1, 'sid' => 6, ), ), 1 => array ( 'logo' => array ( 'id' => 2, 'sid' => 6, ), ), )
$res = array();foreach($a as $v){if(!isset($res[$v['logo']['sid']])) $res[$v['logo']['sid']] = $v;}print_r(array_values($res));
$last = 0;foreach($a as $r) { foreach($r as $v) { if($last != $v['sid']) echo $v['sid']; $last = $v['sid']; }}
剛剛測試了下,表示您給的代碼有點缺陷,改良了下:
$i ='';
foreach($a as $r=>$v){
foreach($v as $k=>$vv){
if(!stristr($i,$vv['sid'])) {
$i .= $vv['sid'];
echo $vv['sid']; } } }應該沒有什麼問題了
$res = array();foreach($a as $v){if(!isset($res[$v['logo']['sid']])) $res[$v['logo']['sid']] = $v;}print_r(array_values($res));
可能我問題說的不清楚,不過還是解決了,主要是去掉同一欄位的重複的結果。