[MVC_Json序列化]Json字串還原序列化成C#對象

標籤：

上一篇中有Json序列化相關問題得到瞭解決。

那麼結果集為Json串時，如何將Json串轉成C#對象呢？

現舉例說明:

-現有如下字串資料

string k = "{\"rings\":["                +"[[34995.513100000098,4304381.4231000002],[34988.120099999942,4304371.5420999993],"                + "[34995.513100000098,4304381.4231000002],[34988.120099999942,4304371.5420999993],"                + "[34995.513100000098,4304381.4231000002],[34988.120099999942,4304371.5420999993]]],"                + "\"spatialReference\":";

-想將上面的資料轉換成List<point>

public class point {            public decimal x { get; set; }            public decimal y { get; set; }        }

 

步驟1：

-截取字串

public string strCutOut(string str) {            string str1 = str.Substring(str.IndexOf(":[[") + 3, str.IndexOf("]],") - 11);            string str2 = str1.Replace("],[", "]$[");            string str3 = str2.Replace("[", "{‘x‘:");            string str4 = str3.Replace("]", "}");            string str5 = str4.Replace(",", ",‘y‘:");            string str6 = str5.Replace("$", ",");            string str7 = str6.Replace("‘", "\"");            return str7;        }

-得到如下字串

"{\"x\":34995.513100000098,\"y\":4304381.4231000002},

{\"x\":34988.120099999942,\"y\":4304371.5420999993},

{\"x\":34995.513100000098,\"y\":4304381.4231000002},

{\"x\":34988.120099999942,\"y\":4304371.5420999993},

{\"x\":34995.513100000098,\"y\":4304381.4231000002},

{\"x\":34988.120099999942,\"y\":4304371.5420999993}"

 

步驟2：

-引用System.Runtime.Serialization.Json;

-還原序列化字串

public List<point> convertObject(string json)        {            MemoryStream stream2 = new MemoryStream();            DataContractJsonSerializer ser2 = new DataContractJsonSerializer(typeof(List<point>));            StreamWriter wr = new StreamWriter(stream2);            wr.Write(json);            wr.Flush();            stream2.Position = 0;            Object obj = ser2.ReadObject(stream2);            List<point> list = (List<point>)obj;            return list;        }

 

步驟3：

-調用字串截取及還原序列化字串

public void readJson(){            string k = "{\"rings\":["                +"[[34995.513100000098,4304381.4231000002],[34988.120099999942,4304371.5420999993],"                + "[34995.513100000098,4304381.4231000002],[34988.120099999942,4304371.5420999993],"                + "[34995.513100000098,4304381.4231000002],[34988.120099999942,4304371.5420999993]]],"                + "\"spatialReference\":";            string str = strCutOut(k);            string json = "[" + str + "]";            List<point> ls = convertObject(json);        }

 

*得到的結果集ls為:

[MVC_Json序列化]Json字串還原序列化成C#對象