8.3 常用查詢的例子 下面是一些學習如何用MySQL解決一些常見問題的例子。 一些例子使用資料庫表“shop”,包含某個商人的每篇文章(物品號)的價格。假定每個商人的每篇文章有一個單獨的固定價格,那麼(物品,商人)是記錄的主鍵。 你能這樣建立例子資料庫表: CREATE TABLE shop ( article INT(4) UNSIGNED ZEROFILL DEFAULT '0000' NOT NULL, dealer CHAR(20) DEFAULT '' NOT NULL, price DOUBLE(16,2) DEFAULT '0.00' NOT NULL, PRIMARY KEY(article, dealer));INSERT INTO shop VALUES(1,'A',3.45),(1,'B',3.99),(2,'A',10.99),(3,'B',1.45),(3,'C',1.69),(3,'D',1.25),(4,'D',19.95); 好了,例子資料是這樣的: SELECT * FROM shop+---------+--------+-------+| article | dealer | price |+---------+--------+-------+| 0001 | A | 3.45 || 0001 | B | 3.99 || 0002 | A | 10.99 || 0003 | B | 1.45 || 0003 | C | 1.69 || 0003 | D | 1.25 || 0004 | D | 19.95 |+---------+--------+-------+ 8.3.1 列的最大值“最大的物品號是什嗎?” SELECT MAX(article) AS article FROM shop+---------+| article |+---------+| 4 |+---------+ 8.3.2 擁有某個列的最大值的行“找出最貴的文章的編號、商人和價格” 在ANSI-SQL中這很容易用一個子查詢做到: SELECT article, dealer, priceFROM shopWHERE price=(SELECT MAX(price) FROM shop) 在MySQL中(還沒有子查詢)就用2步做到:
- 用一個
SELECT 語句從表中得到最大值。
- 使用該值編出實際的查詢:
SELECT article, dealer, priceFROM shopWHERE price=19.95
另一個解決方案是按價格降序排序所有行並用MySQL特定LIMIT 子句只得到的第一行: SELECT article, dealer, priceFROM shopORDER BY price DESCLIMIT 1 注意:如果有多個最貴的文章( 例如每個19.95),LIMIT 解決方案僅僅顯示他們之一! 8.3.3 列的最大值:按組:只有值“每篇文章的最高的價格是什嗎?” SELECT article, MAX(price) AS priceFROM shopGROUP BY article+---------+-------+| article | price |+---------+-------+| 0001 | 3.99 || 0002 | 10.99 || 0003 | 1.69 || 0004 | 19.95 |+---------+-------+ 8.3.4 擁有某個欄位的組間最大值的行“對每篇文章,找出有最貴的價格的交易者。” 在ANSI SQL 中,我可以用這樣一個子查詢做到: SELECT article, dealer, priceFROM shop s1WHERE price=(SELECT MAX(s2.price) FROM shop s2 WHERE s1.article = s2.article) 在MySQL中,最好是分幾步做到:
- 得到一個表(文章,maxprice)。見8.3.4 擁有某個域的組間最大值的行。
- 對每篇文章,得到對應於儲存最大價格的行。
這可以很容易用一個暫存資料表做到: CREATE TEMPORARY TABLE tmp ( article INT(4) UNSIGNED ZEROFILL DEFAULT '0000' NOT NULL, price DOUBLE(16,2) DEFAULT '0.00' NOT NULL);LOCK TABLES article read;INSERT INTO tmp SELECT article, MAX(price) FROM shop GROUP BY article;SELECT article, dealer, price FROM shop, tmpWHERE shop.article=tmp.articel AND shop.price=tmp.price;UNLOCK TABLES;DROP TABLE tmp; 如果你不使用一個TEMPORARY 表,你也必須鎖定“tmp”表。 “它能一個單個查詢做到嗎?” 是的,但是只有使用我稱之為“MAX-CONCAT詭計”的一個相當低效的詭計: SELECT article, SUBSTRING( MAX( CONCAT(LPAD(price,6,'0'),dealer) ), 7) AS dealer, 0.00+LEFT( MAX( CONCAT(LPAD(price,6,'0'),dealer) ), 6) AS priceFROM shopGROUP BY article;+---------+--------+-------+| article | dealer | price |+---------+--------+-------+| 0001 | B | 3.99 || 0002 | A | 10.99 || 0003 | C | 1.69 || 0004 | D | 19.95 |+---------+--------+-------+ 最後例子當然能通過在客戶程式中分割連結的列使它更有效一點。 8.3.5 使用外鍵不需要外鍵連接2個表。 MySQL 唯一不做的事情是CHECK 以保證你使用的鍵確實在你正在參考資料表中存在,並且它不自動從有一個外鍵定義的表中刪除行。如果你象平常那樣使用你的索引值,它將工作得很好!
CREATE TABLE persons ( id SMALLINT UNSIGNED NOT NULL AUTO_INCREMENT, name CHAR(60) NOT NULL, PRIMARY KEY (id));CREATE TABLE shirts ( id SMALLINT UNSIGNED NOT NULL AUTO_INCREMENT, style ENUM('t-shirt', 'polo', 'dress') NOT NULL, color ENUM('red', 'blue', 'orange', 'white', 'black') NOT NULL, owner SMALLINT UNSIGNED NOT NULL REFERENCES persons, PRIMARY KEY (id));INSERT INTO persons VALUES (NULL, 'Antonio Paz');INSERT INTO shirts VALUES(NULL, 'polo', 'blue', LAST_INSERT_ID()),(NULL, 'dress', 'white', LAST_INSERT_ID()),(NULL, 't-shirt', 'blue', LAST_INSERT_ID());INSERT INTO persons VALUES (NULL, 'Lilliana Angelovska');INSERT INTO shirts VALUES(NULL, 'dress', 'orange', LAST_INSERT_ID()),(NULL, 'polo', 'red', LAST_INSERT_ID()),(NULL, 'dress', 'blue', LAST_INSERT_ID()),(NULL, 't-shirt', 'white', LAST_INSERT_ID());SELECT * FROM persons;+----+---------------------+| id | name |+----+---------------------+| 1 | Antonio Paz || 2 | Lilliana Angelovska |+----+---------------------+SELECT * FROM shirts;+----+---------+--------+-------+| id | style | color | owner |+----+---------+--------+-------+| 1 | polo | blue | 1 || 2 | dress | white | 1 || 3 | t-shirt | blue | 1 || 4 | dress | orange | 2 || 5 | polo | red | 2 || 6 | dress | blue | 2 || 7 | t-shirt | white | 2 |+----+---------+--------+-------+SELECT s.* FROM persons p, shirts s WHERE p.name LIKE 'Lilliana%' AND s.owner = p.id AND s.color <> 'white';+----+-------+--------+-------+| id | style | color | owner |+----+-------+--------+-------+| 4 | dress | orange | 2 || 5 | polo | red | 2 || 6 | dress | blue | 2 |+----+-------+--------+-------+ |