工作中遇到一個問題:要更新一個資料表。
這個表是我自己建立的,有7個欄位,id、name、package等等
建立的時候,因為我把name、package的資訊分別存在兩個文字檔中,
所以我就用Insert方法,一次性將所有的name插入資料庫中。
name全部匯入資料庫中了,但是我的package沒有匯入,這時我仍然想用insert的方法插入,但是不行。
這時候應該利用update的方法。一次更新多條資訊的思路如下:
UPDATE table_name SET field_name = CASE other_field WHEN 1 THEN 'value' WHEN 2 THEN 'value' WHEN 3 THEN 'value' ENDWHERE id IN (1,2,3)
測試代碼如下:
<?php/**function:insert app's apk ,logo_url, document_title,app_desc,package_name*into talbe atable use database db .*///connect database catx.$server='localhost';$user='root';$passwd='root';$port='3306';$dbname='catx';$link=mysql_connect($server,$user,$passwd);if (!$link) {die('Could not connect: ' . mysql_error());}else echo "Connected successfully\n";mysql_select_db("db",$link);//set init variable and start time$st=microtime_float();$table="pydot_g";$path = "txt";$fname_package_name ="package_name.txt";//$handle= @fopen($path."/".$fname_package_name, "r"); $i=1;$sql = "UPDATE pydot_g SET package_name = CASE id "; $ids="";while(($buf[$i]=fgets($handle,512))!==false){ $sql .= sprintf("WHEN %d THEN '%s' ", $i, $buf[$i]); // 拼接SQL語句 $ids .= sprintf("%d,",$i);$i++;} //$ids=implode(',',$ids);$ids.=$i;$sql .= "END WHERE id IN ($ids)"; echo $sql; mysql_query($sql);fclose($handle);mysql_close($link);//echo the results and total time used$et=microtime_float();$t=$et-$st;echo "\r\ninsert into talbe ",$table," ",$i,"times;\r\n";echo "Total time $t seconds.\r\n";//function calculate time ,return a float numberfunction microtime_float(){ list($usec, $sec) = explode(" ", microtime());return ((float)$usec + (float)$sec);}?>