[Node.js]在windows下不得不防的小錯誤

標籤：node.js   socket.io   typeerror   

TypeError: Arguments to path.join must be strings    at f (path.js:204:15)    at Object.filter (native)    at exports.join (path.js:209:40)    at exports.send (E:\nodejs\demo\socket.io-express\node_modules\express\node_modules\connect\lib\middleware\static.js:129:20)    at ServerResponse.res.sendfile (E:\nodejs\demo\socket.io-express\node_modules\express\lib\response.js:186:3)    at io.sockets.on.socket.emit.text (E:\nodejs\demo\socket.io-express\app.js:8:6)    at callbacks (E:\nodejs\demo\socket.io-express\node_modules\express\lib\router\index.js:272:11)    at param (E:\nodejs\demo\socket.io-express\node_modules\express\lib\router\index.js:246:11)    at pass (E:\nodejs\demo\socket.io-express\node_modules\express\lib\router\index.js:253:5)    at Router._dispatch (E:\nodejs\demo\socket.io- express\node_modules\express\lib\router\index.js:280:5)

Node.js中的兩個模組Socket.io 和Express做整合的時候出現了以下的錯誤：

var express = require(‘express‘);var app = module.exports = express.createServer(),    io = require(‘socket.io‘).listen(app); app.listen(3000); app.get(‘/‘, function(req, res){    res.sendfile(__dirname + ‘/index.html‘);}); io.sockets.on(‘connection‘, function(socket){    socket.emit(‘welcome‘, {text: ‘OH HAI! U R CONNECTED!‘});});

錯誤原因：

主要的錯誤原因是上面代碼第8行，將代碼改為以下形式即可工作。

var express = require(‘express‘);var app = module.exports = express.createServer(),    io = require(‘socket.io‘).listen(app);app.listen(3000);app.get(‘/‘, function(req, res){res.sendfile(‘/index.html‘, {root: __dirname});});io.sockets.on(‘connection‘, function(socket){socket.emit(‘welcome‘, {text: ‘OH HAI! U R CONNECTED‘});});

在win 下 傳

__dirname + ‘/index.html‘ -> E:\nodejs\demo/index.html

貌似,那裡用 url 解析模組.最後解析的結果不是windows 那種路徑樣子..

然後到建立流的時候路徑就不對了..

參考資料：https://github.com/visionmedia/send