第八周上機任務項目2-Time類中的運算子多載

01./*     02.* 程式的著作權和版本聲明部分     03.* Copyright (c)2013, 煙台大學電腦學院學生     04.* All rightsreserved.     05.* 檔案名稱：ctime .cpp                                06.* 作    者：趙冠哲                                 07.* 完成日期：2013年4月19日     08.* 版本號碼： v1.0           09.* 輸入描述：     10.* 問題描述：   11.*/#include <iostream>using namespace std;class CTime{private:    unsigned short int hour;    // 時    unsigned short int minute;  // 分    unsigned short int second;  // 秒public:    CTime(int h=0,int m=0,int s=0){setTime(h, m, s);}    void setTime(int h,int m,int s){if (h >= 60 || m >= 60 || s >= 60) return; hour = h, minute = m, second = s;}    void display(){cout << hour << ":" << minute << ":" << second << endl;};    //比較子(二目)的重載bool operator > (CTime &t);bool operator < (CTime &t);    bool operator >= (CTime &t);bool operator <= (CTime &t);    bool operator == (CTime &t);bool operator != (CTime &t);//二目運算子的重載CTime operator+(CTime &c);//返回c所規定的時、分、秒後的時間，例t1(8,20,25),t2(11,20,50)，t1+t2為:41:15    CTime operator-(CTime &c);//對照+理解CTime operator+(int s);//返回s秒後的時間    CTime operator-(int s);//返回s秒前的時間    //一目運算子的重載    CTime operator++(int);//後置++，下一秒CTime operator++();//前置++，下一秒    CTime operator--(int);//後置--，前一秒    CTime operator--();//前置--，前一秒//賦值運算子的重載    CTime operator+=(CTime &c);    CTime operator-=(CTime &c);    CTime operator+=(int s);//返回s秒後的時間    CTime operator-=(int s);//返回s秒前的時間};//下面實現所有的運算子多載代碼。//為簡化編程，請注意通過調用已有函數，利用好各函數之間的關係bool CTime::operator > (CTime &t){    if (hour>t.hour)        return true;else if(hour==t.hour&&minute>t.minute)return true;    else if(minute==t.minute&&second>t.second)        return true;    else        return false;}bool CTime::operator<(CTime &t){    if(hour<t.hour)        return true;    else if(hour==t.hour&&minute<t.minute)        return true;    else if(minute==t.minute&&second<t.second)        return true;elsereturn false;}bool CTime::operator>= (CTime &t){    if (hour>t.hour)        return true;else if(hour==t.hour&&minute>t.minute)        return true;else if (minute==t.minute && second>=t.second)        return true;else        return false;}bool CTime::operator<=(CTime &t){    if (hour<t.hour)        return true;    else if(hour==t.hour&&minute<t.minute)        return true;    else if (minute==t.minute&&second<=t.second)        return true;    else        return false;}bool CTime::operator==(CTime &t){    if (hour==t.hour&&minute==t.minute&&second==t.second)        return true;    else        return false;}bool CTime::operator!=(CTime &t){    if (hour==t.hour&&minute==t.minute&&second==t.second)        return false;    else        return true;}CTime CTime::operator+(CTime &c){CTime ct(*this);    if (ct.second+c.second>=60)    {        ct.second=ct.second+c.second-60;        ++ct.minute;    }    else        ct.second=ct.second+c.second;    if (ct.minute+c.minute>=60)    {        ct.minute=ct.minute+c.minute-60;        ++ct.hour;    }else        ct.minute=ct.minute+c.minute;    if (ct.hour+c.hour>=60)        ct.hour=ct.hour+c.hour-60;    else        ct.hour=ct.hour+c.hour;    return ct;}CTime CTime::operator-(CTime &c){    CTime ct(*this);    if (ct.second<c.second)    {        --ct.minute;        ct.second=ct.second+60-c.second;    }    else        ct.second=ct.second-c.second;    if (ct.minute<c.minute)    {        --ct.hour;        ct.minute=ct.minute+60-c.minute;    }    else        ct.minute=ct.minute-c.minute;    if (ct.hour < c.hour)ct.hour = ct.hour + 24 - c.hour;    else        ct.hour=ct.hour-c.hour;    return ct;}CTime CTime::operator+(int s){    CTime ct;    ct.hour=s/3600;    s=s%3600;    ct.minute=s/60;    ct.second=s%60;    return (*this + ct);}CTime CTime::operator-(int s){    CTime ct;    ct.hour=s/3600;    s=s%3600;ct.minute=s/60;ct.second=s%60;    return (*this - ct);}CTime CTime::operator++(int){    CTime tp(*this);    *this=*this+1;    return tp;}CTime CTime::operator++(){    return (*this=*this+1);}CTime CTime::operator--(int){    CTime tp(*this);    *this=*this-1;    return tp;}CTime CTime::operator--(){    return(*this=*this-1);//需要改變其值}CTime CTime::operator+=(CTime &c){    return (*this=*this+c);}CTime CTime::operator-=(CTime &c){    return (*this=*this - c);}CTime CTime::operator+=(int s){    return (*this=*this+s);}CTime CTime::operator-=(int s){    return (*this=*this-s);}int main(){    CTime t1(8, 20, 25), t2(11, 20, 50), t;    cout << "t1為：";    t1.display();    cout << "t2為：";    t2.display();    cout << "下面比較兩個時間大小：\n";    if (t1 > t2) cout << "t1>t2" << endl;    if (t1 < t2) cout << "t1<t2" << endl;    if (t1 == t2) cout << "t1＝t2" << endl;    if (t1 != t2) cout << "t1≠t2" << endl;    if (t1 >= t2) cout << "t1≥t2" << endl;    if (t1 <= t2) cout << "t1≤t2" << endl;    cout << endl;    //下面自行設計對其他運算子的重載的測試    t = t1 + t2;    cout << "t1+t2=";    t.display();    t = t1 - t2;    cout << "t1-t2=";    t.display();    cout << "t1後退123秒。t1+123=";    t1 = t1 + 123;    t1.display();    cout << "t2前進321秒。t2-321=";    t2 = t2 - 321;    t2.display();    cout << "++t1=";    (++t1).display();cout << "t1=";t1.display();cout << "--t1=";(--t1).display();    cout << "t1=";    t1.display();    cout << "t2++=";    (t2++).display();    cout << "t2=";    t2.display();    cout << "t2--=";    (t2--).display();    cout << "t2=";    t2.display();    cout << "(t1+=t2)=";    t1+=t2;t1.display();    cout << "(t1-=t2)=";    t1-=t2;    t1.display();    cout<< "t1前進365秒。(t1-=365)=";    t1-=365;t1.display();cout << "t2後退3秒。(t2+=3)=";t2+=3;    t2.display();    return 0;}

運行結果：