Oracle 統計某一年中的1-12個月的資料總和(非常實用),oracle1-12
實戰案例
查詢2015年1月到12個月的所有實有人口數量和往年2014年1月到12個月的實有人口數量,沒有的月份顯示 人口數量為0.類似效果
建立表
create table PERSONSITUATION( id NUMBER not null, rdate DATE, nums NUMBER)
插入資料
insert into PERSONSITUATION (id, rdate, nums) values (1, to_date('26-01-2015', 'dd-mm-yyyy'), 131);insert into PERSONSITUATION (id, rdate, nums) values (2, to_date('27-01-2013', 'dd-mm-yyyy'), 232);insert into PERSONSITUATION (id, rdate, nums) values (3, to_date('18-10-2013', 'dd-mm-yyyy'), 222);insert into PERSONSITUATION (id, rdate, nums) values (4, to_date('20-01-2015', 'dd-mm-yyyy'), 232);insert into PERSONSITUATION (id, rdate, nums) values (5, to_date('28-01-2015', 'dd-mm-yyyy'), 422);insert into PERSONSITUATION (id, rdate, nums) values (6, to_date('26-02-2015', 'dd-mm-yyyy'), 232);insert into PERSONSITUATION (id, rdate, nums) values (7, to_date('29-01-2014', 'dd-mm-yyyy'), 225);insert into PERSONSITUATION (id, rdate, nums) values (8, to_date('31-01-2015', 'dd-mm-yyyy'), 111);insert into PERSONSITUATION (id, rdate, nums) values (9, to_date('25-01-2013', 'dd-mm-yyyy'), 211);insert into PERSONSITUATION (id, rdate, nums) values (10, to_date('25-01-2013', 'dd-mm-yyyy'), 251);insert into PERSONSITUATION (id, rdate, nums) values (11, to_date('25-01-2013', 'dd-mm-yyyy'), 262);insert into PERSONSITUATION (id, rdate, nums) values (12, to_date('25-08-2015', 'dd-mm-yyyy'), 233);insert into PERSONSITUATION (id, rdate, nums) values (13, to_date('25-01-2013', 'dd-mm-yyyy'), 211);insert into PERSONSITUATION (id, rdate, nums) values (14, to_date('25-02-2014', 'dd-mm-yyyy'), 222);insert into PERSONSITUATION (id, rdate, nums) values (15, to_date('25-03-2012', 'dd-mm-yyyy'), 209);insert into PERSONSITUATION (id, rdate, nums) values (16, to_date('25-01-2012', 'dd-mm-yyyy'), 219);
常見的統計中如下Sql語句,只查詢到了資料中有的月,如果沒有就什麼也沒有顯示,和明顯不符合1-12個月的12條資料統計
select to_char(rdate,'yyyy-mm') rdate,sum(nums) nums from personsituation where to_char(rdate,'yyyy')='2015' group by to_char(rdate,'yyyy-mm') order by rdate
正確的分析是:必須是12條資料,而且是統計的結果的12條資料,從這裡入手編寫如下Sql語句,顯示12個列的統計資料,先查詢出一年的資料,然後再串連另外一條資料拼接
select sum(decode(to_char(rdate,'mm'),'01',nums,0)) nums01,sum(decode(to_char(rdate,'mm'),'02',nums,0)) nums02, sum(decode(to_char(rdate,'mm'),'03',nums,0)) nums03,sum(decode(to_char(rdate,'mm'),'04',nums,0)) nums04, sum(decode(to_char(rdate,'mm'),'05',nums,0)) nums05,sum(decode(to_char(rdate,'mm'),'06',nums,0)) nums06, sum(decode(to_char(rdate,'mm'),'07',nums,0)) nums07,sum(decode(to_char(rdate,'mm'),'08',nums,0)) nums08, sum(decode(to_char(rdate,'mm'),'09',nums,0)) nums09,sum(decode(to_char(rdate,'mm'),'10',nums,0)) nums10, sum(decode(to_char(rdate,'mm'),'11',nums,0)) nums11,sum(decode(to_char(rdate,'mm'),'12',nums,0)) nums12 from personsituation where to_char(rdate,'yyyy')='2015'
而前端頁面顯示的結果有兩種可能性,一種是橫向展示,一種是縱向展示,可以使用下面的sql語句進行列轉行的轉換得到如下結果
select * from ( select sum(decode(to_char(rdate,'mm'),'01',nums,0)) nums01,sum(decode(to_char(rdate,'mm'),'02',nums,0)) nums02, sum(decode(to_char(rdate,'mm'),'03',nums,0)) nums03,sum(decode(to_char(rdate,'mm'),'04',nums,0)) nums04, sum(decode(to_char(rdate,'mm'),'05',nums,0)) nums05,sum(decode(to_char(rdate,'mm'),'06',nums,0)) nums06, sum(decode(to_char(rdate,'mm'),'07',nums,0)) nums07,sum(decode(to_char(rdate,'mm'),'08',nums,0)) nums08, sum(decode(to_char(rdate,'mm'),'09',nums,0)) nums09,sum(decode(to_char(rdate,'mm'),'10',nums,0)) nums10, sum(decode(to_char(rdate,'mm'),'11',nums,0)) nums11,sum(decode(to_char(rdate,'mm'),'12',nums,0)) nums12 from personsituation where to_char(rdate,'yyyy')='2015' ) unpivot (sum2015 for years in (nums01,nums02,nums03,nums04,nums05,nums06,nums07,nums08,nums09,nums10,nums11,nums12) )
最後一步就是和往年的資料對比使用left join查詢
select A.years,A.SUM2015,B.SUM2014 from (select * from ( select sum(decode(to_char(rdate,'mm'),'01',nums,0)) nums01,sum(decode(to_char(rdate,'mm'),'02',nums,0)) nums02, sum(decode(to_char(rdate,'mm'),'03',nums,0)) nums03,sum(decode(to_char(rdate,'mm'),'04',nums,0)) nums04, sum(decode(to_char(rdate,'mm'),'05',nums,0)) nums05,sum(decode(to_char(rdate,'mm'),'06',nums,0)) nums06, sum(decode(to_char(rdate,'mm'),'07',nums,0)) nums07,sum(decode(to_char(rdate,'mm'),'08',nums,0)) nums08, sum(decode(to_char(rdate,'mm'),'09',nums,0)) nums09,sum(decode(to_char(rdate,'mm'),'10',nums,0)) nums10, sum(decode(to_char(rdate,'mm'),'11',nums,0)) nums11,sum(decode(to_char(rdate,'mm'),'12',nums,0)) nums12 from personsituation where to_char(rdate,'yyyy')='2015' ) unpivot (sum2015 for years in (nums01,nums02,nums03,nums04,nums05,nums06,nums07,nums08,nums09,nums10,nums11,nums12) )) Aleft join (select * from ( select sum(decode(to_char(rdate,'mm'),'01',nums,0)) nums01,sum(decode(to_char(rdate,'mm'),'02',nums,0)) nums02, sum(decode(to_char(rdate,'mm'),'03',nums,0)) nums03,sum(decode(to_char(rdate,'mm'),'04',nums,0)) nums04, sum(decode(to_char(rdate,'mm'),'05',nums,0)) nums05,sum(decode(to_char(rdate,'mm'),'06',nums,0)) nums06, sum(decode(to_char(rdate,'mm'),'07',nums,0)) nums07,sum(decode(to_char(rdate,'mm'),'08',nums,0)) nums08, sum(decode(to_char(rdate,'mm'),'09',nums,0)) nums09,sum(decode(to_char(rdate,'mm'),'10',nums,0)) nums10, sum(decode(to_char(rdate,'mm'),'11',nums,0)) nums11,sum(decode(to_char(rdate,'mm'),'12',nums,0)) nums12 from personsituation where to_char(rdate,'yyyy')='2014' ) unpivot (sum2014 for years in (nums01,nums02,nums03,nums04,nums05,nums06,nums07,nums08,nums09,nums10,nums11,nums12) )) B on A.years = B.years
實現與一樣的資料,可以將sql中的nums01...nums12改為1月...12月
select A.years,A.SUM1,B.SUM2 from (select * from ( select sum(decode(to_char(rdate,'mm'),'01',nums,0)) 一月,sum(decode(to_char(rdate,'mm'),'02',nums,0)) 二月, sum(decode(to_char(rdate,'mm'),'03',nums,0)) 三月,sum(decode(to_char(rdate,'mm'),'04',nums,0)) 四月, sum(decode(to_char(rdate,'mm'),'05',nums,0)) 五月,sum(decode(to_char(rdate,'mm'),'06',nums,0)) 六月, sum(decode(to_char(rdate,'mm'),'07',nums,0)) 七月,sum(decode(to_char(rdate,'mm'),'08',nums,0)) 八月, sum(decode(to_char(rdate,'mm'),'09',nums,0)) 九月,sum(decode(to_char(rdate,'mm'),'10',nums,0)) 十月, sum(decode(to_char(rdate,'mm'),'11',nums,0)) 十一月,sum(decode(to_char(rdate,'mm'),'12',nums,0)) 十二月 from personsituation where to_char(rdate,'yyyy')= '2015' ) unpivot (sum1 for years in (一月,二月,三月,四月,五月,六月,七月,八月, 九月,十月,十一月,十二月) )) Aleft join (select * from ( select sum(decode(to_char(rdate,'mm'),'01',nums,0)) 一月,sum(decode(to_char(rdate,'mm'),'02',nums,0)) 二月, sum(decode(to_char(rdate,'mm'),'03',nums,0)) 三月,sum(decode(to_char(rdate,'mm'),'04',nums,0)) 四月, sum(decode(to_char(rdate,'mm'),'05',nums,0)) 五月,sum(decode(to_char(rdate,'mm'),'06',nums,0)) 六月, sum(decode(to_char(rdate,'mm'),'07',nums,0)) 七月,sum(decode(to_char(rdate,'mm'),'08',nums,0)) 八月, sum(decode(to_char(rdate,'mm'),'09',nums,0)) 九月,sum(decode(to_char(rdate,'mm'),'10',nums,0)) 十月, sum(decode(to_char(rdate,'mm'),'11',nums,0)) 十一月,sum(decode(to_char(rdate,'mm'),'12',nums,0)) 十二月 from personsituation where to_char(rdate,'yyyy')= '2014' ) unpivot (sum2 for years in (一月,二月,三月,四月,五月,六月,七月,八月, 九月,十月,十一月,十二月) )) B on A.years = B.years
行轉列,列轉行有不懂得地方可以參考文章:http://blog.csdn.net/xiaokui_wingfly/article/details/42419207 覺得不錯記得點贊瀏覽,謝謝