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oracle 三表關聯查詢CreationTime--2018年7月4日17點52分Author:Marydon
左串連實現三表關聯
表A---------------------------------關聯第一張表B-----------------------關聯第二張表c
1.文法
select * from 表名A left join 表B on A.columnX=B.columnM and A.columnY=B.columnN left join 表c on 表A=表c的id
2.應用情境
四張表 GJPT_BASY、GJZY_BASY、GJPT_BASY_ERROR、GJZY_BASY_ERROR
根據四張表,要求返回:醫學機構名稱,醫學機構編號,總數,合格數和問題數
3.SQL實現
SELECT TEMP1.*, TEMP2.HEGESUM, TEMP3.TROUBLESUM FROM (SELECT T1.YLNAME, T1.YLCODE, SUM(RS1) AS YLSUM--總數 FROM (SELECT COUNT(1) AS RS1, HDSD00_11_118 AS YLNAME, HDSD00_11_119 AS YLCODE FROM GJPT_BASY GROUP BY HDSD00_11_119, HDSD00_11_118 UNION ALL SELECT COUNT(1) AS RS1, HDSD00_12_133 AS YLNAME, HDSD00_12_134 AS YLCODE FROM GJZY_BASY GROUP BY HDSD00_12_133, HDSD00_12_134 UNION ALL SELECT COUNT(1) AS RS1, HDSD00_11_118 AS YLNAME, HDSD00_11_119 AS YLCODE FROM GJPT_BASY_ERROR GROUP BY HDSD00_11_119, HDSD00_11_118 UNION ALL SELECT COUNT(1) AS RS1, HDSD00_12_133 AS YLNAME, HDSD00_12_134 AS YLCODE FROM GJZY_BASY_ERROR GROUP BY HDSD00_12_133, HDSD00_12_134) T1 GROUP BY T1.YLNAME, T1.YLCODE) TEMP1 LEFT JOIN (SELECT * FROM (SELECT T2.YLNAME, T2.YLCODE, SUM(RS2) AS HEGESUM--合格數 FROM (SELECT COUNT(1) AS RS2, HDSD00_11_118 AS YLNAME, HDSD00_11_119 AS YLCODE FROM GJPT_BASY GROUP BY HDSD00_11_119, HDSD00_11_118 UNION ALL SELECT COUNT(1) AS RS2, HDSD00_12_133 AS YLNAME, HDSD00_12_134 AS YLCODE FROM GJZY_BASY GROUP BY HDSD00_12_133, HDSD00_12_134) T2 GROUP BY T2.YLNAME, T2.YLCODE)) TEMP2 ON TEMP2.YLNAME = TEMP1.YLNAME AND TEMP2.YLCODE = TEMP1.YLCODE LEFT JOIN (SELECT * FROM (SELECT T3.YLNAME, T3.YLCODE, SUM(RS3) TROUBLESUM--問題數 FROM (SELECT COUNT(1) AS RS3, HDSD00_11_118 AS YLNAME, HDSD00_11_119 AS YLCODE FROM GJPT_BASY_ERROR GROUP BY HDSD00_11_119, HDSD00_11_118 UNION ALL SELECT COUNT(1) AS RS3, HDSD00_12_133 AS YLNAME, HDSD00_12_134 AS YLCODE FROM GJZY_BASY_ERROR GROUP BY HDSD00_12_133, HDSD00_12_134) T3 GROUP BY T3.YLNAME, T3.YLCODE)) TEMP3 ON TEMP3.YLNAME = TEMP1.YLNAME AND TEMP3.YLCODE = TEMP1.YLCODE WHERE TEMP3.YLCODE=‘41580781841010511A1001‘;
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oracle 三表關聯查詢